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2 years ago

3. How does a carbon-14 atom change back into a nitrogen atom?

2 answers:

5 0

<em>Carbon 14 change back into the stable nuclei Nitrogen by </em><em>emitting electron and electron antineutron.</em>

<u>Explanation:-</u>

Carbon 14 is one of the radioactive isotope elements that contains 6 protons and 8 neutron elements.

A general chemical reaction of Carbon 14 is given below.

$14_{6} C \rightarrow 14_{7} N+B e t a^{-1}$

This above reaction can be categorized under Nuclear Reaction. When atomic number 6 (Carbon) was irradiated, Beta ray emission happen and new stable nuclei with atomic number 7 (Nitrogen) formed without change in atomic mass of any nuclei. As well as some amount of energy also emitted through this reaction.

madreJ [45]2 years ago

4 0

Answer: an electron and an electron antineutrino, one of the neutrons in the carbon-14 atom decays to a proton and the carbon-14 (half-life of 5,700 ± 40 years) decays into the stable (non-radioactive) isotope nitrogen-14.

Neutrons: 8

Isotope mass: 14.003241 u

Symbol names: 14C; carbon-14, C-14, radioca...

Protons: 6

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poizon [28]

Answer: $3.8\times 10^{-3}M$

Explanation:

Moles of $NOCl$ = 1 mole

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Initial concentration of $NOCl$ = 1 M

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The given balanced equilibrium reaction is,

$2NOCl(g)\rightleftharpoons 2NO(g)+Cl_2(g)$

Initial conc. 1 M 0M 1 M

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$K_c=\frac{[NO]^2[Cl_2]}{[NOCl]^2}$

The $K_c$ = $1.6\times 10^{-5}}$

Now put all the given values in this expression, we get :

${1.6\times 10^{-5}}=\frac{(2x)^2\times (1+x)}{(1-2x)^2}$

By solving the term 'x', we get :

$x=0.0019$

Concentration of $NO$ at equilibrium= (2x) M = $2\times 0.0019=3.8\times 10^{-3}M$

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2 years ago

Explain, in terms of electrons, why the radius of a calcium ion is smaller than the radius of a calcium atom.

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