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3 years ago

3. How does a carbon-14 atom change back into a nitrogen atom?

2 answers:

5 0

<em>Carbon 14 change back into the stable nuclei Nitrogen by </em><em>emitting electron and electron antineutron.</em>

<u>Explanation:-</u>

Carbon 14 is one of the radioactive isotope elements that contains 6 protons and 8 neutron elements.

A general chemical reaction of Carbon 14 is given below.

$14_{6} C \rightarrow 14_{7} N+B e t a^{-1}$

This above reaction can be categorized under Nuclear Reaction. When atomic number 6 (Carbon) was irradiated, Beta ray emission happen and new stable nuclei with atomic number 7 (Nitrogen) formed without change in atomic mass of any nuclei. As well as some amount of energy also emitted through this reaction.

madreJ [45]3 years ago

4 0

Answer: an electron and an electron antineutrino, one of the neutrons in the carbon-14 atom decays to a proton and the carbon-14 (half-life of 5,700 ± 40 years) decays into the stable (non-radioactive) isotope nitrogen-14.

Neutrons: 8

Isotope mass: 14.003241 u

Symbol names: 14C; carbon-14, C-14, radioca...

Protons: 6

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There are seven types of crystals. Which of these is not one of the seven?

Gelneren [198K]

The answer is B. tetraclinic

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3 years ago

Read 2 more answers

Materials expand when heated. Consider a metal rod of length L0 at temperature T0. If the temperature is changed by an amount ΔT

marysya [2.9K]

Answer:

(a) The length at temperature 180°C is 40.070 cm

(b) The length at temperature 90°C is 64.976 inches

Explanation:

(a) The given parameters are

The thermal expansion coefficient, α for steel = 1.24 × 10⁻⁵/°C

The initial length of the steel L₀ = 40 cm

The initial temperature, t₀ = 40°C

The length at temperature 180°C = L

Therefore, from the given relation, for change in length, ΔL, we have;

ΔL = α × L₀ × ΔT

The amount the temperature changed ΔT = 180°C - 40°C = 140°C

Therefore, the change in length, ΔL, is found as follows;

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 40 × 140°C = 0.07 cm

Therefore, L = L₀ + ΔL = 40 + 0.07 = 40.07 cm

The length at temperature 180°C = 40.07 cm

(b) Given that the length at T = 120°C is 65 in., we have;

The temperature at which the new length is sought = 90°C

The amount the temperature changed ΔT = 90°C - 120°C = -30°C

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 65 × -30°C = -0.024375 inches

The length, L at 90°C is therefore, L = L₀ + ΔL = 65 - 0.024375 = 64.976 in.

The length at temperature 90°C = 64.976 inches

Therefore;

L = 60 + α × 60 × (T - 150°C)

L = 60 + α × 60 × T - 9000 × α

L(T, α) = 60·α·T - 9000·α + 60

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3 years ago

Neon lamps, is composed of 90.483% of 20ne, 0.271% of 21ne, and 9.253% of 22ne. the 20ne atoms have a mass of 19.992 u, 21ne ato

WITCHER [35]

20.181 u

The average atomic mass of Ne is the <em>weighted average</em> of the atomic masses of its isotopes.

We multiply the atomic mass of each isotope by a number representing its relative importance (i.e., its % abundance).

Thus,

Avg. at. mass

= (0.904 83× 19.992 u) + (0.002 71 × 20.994) + (0.092 53× 21.991 u)

= 18.0894 u + 0.0569 u + 2.0348 u = 20.181 u

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3 years ago

I do not understand this question

boyakko [2]

Answer:

the answer should be c

Explanation: why because 37/19 k toward 0+1e +37/18 AR is equivalent to the beta decay and it describes the best beta decay in the formula.

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3 years ago

A typical person has an average heart rate of 75.0 beats/min. Pay close attention to significant figures in this question.

frozen [14]

The number of beats the person have in 1.7 years is 6.7 x 10⁷ beats.

<h3>Number of beats of the person</h3>

The number of beats of the person is calculated as follows;

n = bt

where;

b is the beat rate
n is number of beats
t is time or duration

b = 75 beats/min

t = 1.7 years = 893520 mins

n = 75 beats/min x 893520 mins

n = 67,014,000

n = 6.7 x 10⁷ beats

Thus, the number of beats the person have in 1.7 years is 6.7 x 10⁷ beats.

Learn more about number of beats here: brainly.com/question/28245460

#SPJ1

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1 year ago