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3 years ago

3. How does a carbon-14 atom change back into a nitrogen atom?

2 answers:

5 0

Carbon 14 change back into the stable nuclei Nitrogen by emitting electron and electron antineutron.

Explanation:-

Carbon 14 is one of the radioactive isotope elements that contains 6 protons and 8 neutron elements.

A general chemical reaction of Carbon 14 is given below.

$14_{6} C \rightarrow 14_{7} N+B e t a^{-1}$

This above reaction can be categorized under Nuclear Reaction. When atomic number 6 (Carbon) was irradiated, Beta ray emission happen and new stable nuclei with atomic number 7 (Nitrogen) formed without change in atomic mass of any nuclei. As well as some amount of energy also emitted through this reaction.

madreJ [45]3 years ago

4 0

Answer: an electron and an electron antineutrino, one of the neutrons in the carbon-14 atom decays to a proton and the carbon-14 (half-life of 5,700 ± 40 years) decays into the stable (non-radioactive) isotope nitrogen-14.

Neutrons: 8

Isotope mass: 14.003241 u

Symbol names: 14C; carbon-14, C-14, radioca...

Protons: 6

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For the reaction A +B+ C D E, the initial reaction rate was measured for various initial concentrations of reactants. The follow

lora16 [44]

Answer:

Rate constant of the reaction is $3.3\times 10^{-3} M^{-2} s^{-1}$ .

Explanation:

A + B + C → D + E

Let the balanced reaction be ;

aA + bB + cC → dD + eE

Expression of rate law of the reaction will be written as:

$R=k[A]^a[B]^b[C]^c$

Rate(R) of the reaction in trail 1 ,when :

$[A]=0.30 M,[B]=0.30 M,[C]=0.30 M$

$R=9.0\times 10^{-5} M/s$

$9.0\times 10^{-5} M/s=k[0.30 M]^a[0.30 M]^b[0.30 M]^c$ ...[1]

Rate(R) of the reaction in trail 2 ,when :

$[A]=0.30 M,[B]=0.30 M,[C]=0.90 M$

$R=2.7\times 10^{-4} M/s$

$2.7\times 10^{-4} M/s=k[0.30 M]^a[0.30 M]^b[0.90 M]^c$ ...[2]

Rate(R) of the reaction in trail 3 ,when :

$[A]=0.60 M,[B]=0.30 M,[C]=0.30 M$

$R=3.6\times 10^{-4} M/s$

$3.6\times 10^{-4} M/s=k[0.60 M]^a[0.30 M]^b[0.30 M]^c$ ...[3]

Rate(R) of the reaction in trail 4 ,when :

$[A]=0.60 M,[B]=0.60 M,[C]=0.30 M$

$R=3.6\times 10^{-4} M/s$

$3.6\times 10^{-4} M/s=k[0.60 M]^a[0.60 M]^b[0.30 M]^c$ ...[4]

By [1] ÷ [2], we get value of c ;

c = 1

By [3] ÷ [4], we get value of b ;

b = 0

By [2] ÷ [3], we get value of a ;

a = 2

Rate law of reaction is :

$R=k[A]^2[B]^0[C]^1$

Rate constant of the reaction = k

$9.0\times 10^{-5} M/s=k[0.30 M]^2[0.30 M]^0[0.30 M]^1$

$k=\frac{9.0\times 10^{-5} M/s}{[0.30 M]^2[0.30 M]^0[0.30 M]^1}$

$k=3.3\times 10^{-3} M^{-2} s^{-1}$

7 0

3 years ago

For the following reaction,

jeka94

Answer:

The answer to your question is:

1.- CO

2.- 0.414 moles of CO2

Explanation:

Data

2CO + O2 ⇒ 2CO2

CO = 0.414 moles

O2 = 0.418

Process

theoretical ratio CO/O2 = 2/1 = 1

experimental ratio CO/O2 = 0.414/0.418 = 0.99

Then the limiting reactant is CO

2.-

2 moles of CO --------------- 2 moles of CO2

0.414 moles of CO --------- x

x = (0.414 x 2) / 2

x = 0.414 moles of CO2

5 0

3 years ago

Which of the following is altered by a catalyst?

Vika [28.1K]

In chemistry, a catalyst can speed up the reaction (or make it initiate easier) by altering the activation energy, lowering it enough to allow the reactants to react more easily. Some negative catalysts or inhibitors can do the same by increasing the activation energy.

4 0

3 years ago

Spell out full name of compound

Margarita [4]

Hydroxide is the full name of the compound.

Hope this Helped!

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3 years ago

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The Earth's biosphere is consists of

r-ruslan [8.4K]

Answer:

The Earth's bioshere consist of the parts of Earth where life exists. Ecosystems.