Hi my friend, since momentum is always conserved without external forces, the momentum after the collosion will still be 0.06 kg*m/s. Hope it helps☺
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Carry energy</h2>
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Hope this helped :)
~pinetree
Answer:
2 x 10^20 N
Explanation:
Me = 5.98 x 10^24 kg
Mm = 7.36 x 10^22 kg
r = 3.82 x 10^5 km = 3.82 x 10^8 m
The gravitational force between earth and moon is
F = G Me x Mm / r^2
F = (6.67 x 10^-11 x 5.98 x 10^24 x 7.36 x 10^22) / (3.82 x 10^8 x 3.82 x 10^8)
F = 2 x 10^20 N
Answer: v = 6.0 m/s
Explanation:
T = m(v²/R - g)
(T/m + g)R = v²
v = √((79.0/0.98 + 9.81)0.40) = 6.0140... ≈ 6.0 m/s
Answer: it will take 8.33s for the tiger to land
Explanation: