You have to use the specific heat equation.
Q = cmΔT where Q is the energy, c is specific heat, m is mass, and ΔT is change in temp.
So we can substitute our variables into the equation.
30000J = (390g)(3.9J*g/C)ΔT
Solving for ΔT, we get:
30000J/[(390g)*(3.9J*g/C) = ΔT
ΔT = 19.72386588C
I'm assuming the temperature is C, since it was not specified.
Hope this helps!
The correct answer is rock cycle
The formula for calcium oxide is CaO.
Answer:
Goal or Field Goal
Explanation:
It is a goal in a sport like hockey or it is a field goal in football.
The power is 833.3 W
Explanation:
First of all, we need to calculate the work done in lifting the barbell, which is equal to the change in gravitational potential energy of the barbell:
![W=(mg)h](https://tex.z-dn.net/?f=W%3D%28mg%29h)
where
mg = 1250 N is the weight of the barbell
h = 2 m is the change in height
Substituting,
![W=(1250)(2)=2500 J](https://tex.z-dn.net/?f=W%3D%281250%29%282%29%3D2500%20J)
Now we can calculate the power, which is equal to the work done per unit time:
![P=\frac{W}{t}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7BW%7D%7Bt%7D)
where
W = 2500 J is the work done
t = 3 s is the time taken
Substituting,
![P=\frac{2500}{3}=833.3 W](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B2500%7D%7B3%7D%3D833.3%20W)
Learn more about power:
brainly.com/question/7956557
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