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Genrish500 [490]
3 years ago
5

What is stoichiometry used for

Chemistry
2 answers:
Julli [10]3 years ago
4 0

Answer:

Explanation:

they measures these quantitative relationships. But not dating relationships, but the amount of products and reactants that are produced or needed in a given reaction.

Dennis_Churaev [7]3 years ago
3 0

Answer:

Stoichiometry measures these quantitative relationships, and is used to determine the amount of products and reactants that are produced or needed in a given reaction.

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zheka24 [161]
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4 0
3 years ago
Determine the total number of atoms contain in a 2.00 moles of Ni
spayn [35]

Answer:

2.00 moles of Ni has 1.2 *10^24 atoms

Explanation:

Step 1: Data given

Number of moles Ni = 2.00 moles

Number of Avogadro = 6.022*10^23 /mol

Step 2: Calculate number of atoms

Number of particles (=atoms) = Number of Avogadro *  number of moles

Number of atoms = 6.022 * 10^23 /mol * 2.00 moles

Number of atoms = 1.2*10^24 atoms

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4 0
3 years ago
In the following equation:
Luda [366]

Answer:

FeCl₃

Explanation:

                 4FeCl₃  +   3O₂     => 2Fe₂O₃+ 6Cl₂

Given =>  7moles     9moles

A simple way to determine which reagent is the limiting reactant is to convert all given data to moles then divide by the respective coefficients of the balanced equation. The smaller value will be the limiting reactant.

                 4FeCl₃     +   3O₂     => 2Fe₂O₃+ 6Cl₂

Given =>  7/4 = 1.75*     9/3 = 3

*Smaller value => FeCl₃ is limiting reactant.  

NOTE: However, when working problems, one must use original mole values given.

   

7 0
3 years ago
How many uL are present in 250 mL of H20? (1 uL = 10^-6 Liters)​
Vanyuwa [196]

Answer:

250000 μL

Explanation:

If         1 L = 1000 mL

Then  X L = 250 mL

X = (1 × 250) / 1000 = 0.25 L

Now we can calculate the number of microliters (μL) in 0.25 L:

if        1 μL = 10⁻⁶ L

then   X μL = 0.25 L

X = (1 × 0.25) / 10⁻⁶  =250000 μL

4 0
3 years ago
For the reaction 2hno3 + mg(oh)2 → mg(no3)2 + 2h2o, how many moles of magnesium nitrate are produced from 8.00 moles of nitric a
Sladkaya [172]
You would get four moles of magnesium nitrate :) you would have to
“ ?molesmg(oh)2 = 8molmg(no3)2 x molmg(oh)2 / 2molhno3 = 4 moles of magnesium nitrate :))) hopefully this helps! <3
7 0
3 years ago
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