Vertex=(-1,0)
x^2-2x-1
y=− ( x + 1 )^2 + 0
Use the vertex form, y=a(x−h)^2+k, to determine the values of a, h, and k.
Find the vertex (h,k) = (-1,0)
the area of a square = length*length =3a*3a=9a^2
Answer:
E
Step-by-step explanation:
