The question is defective, or at least is trying to lead you down the primrose path.
The function is linear, so the rate of change is the same no matter what interval (section) of it you're looking at.
The "rate of change" is just the slope of the function in the section. That's
(change in f(x) ) / (change in 'x') between the ends of the section.
In Section A:Length of the section = (1 - 0) = 1f(1) = 5f(0) = 0change in the value of the function = (5 - 0) = 5Rate of change = (change in the value of the function) / (size of the section) = 5/1 = 5
In Section B:Length of the section = (3 - 2) = 1 f(3) = 15f(2) = 10change in the value of the function = (15 - 10) = 5Rate of change = (change in the value of the function) / (size of the section) = 5/1 = 5
Part A:The average rate of change of each section is 5.
Part B:The average rate of change of Section B is equal to the average rate of change of Section A.
Explanation:The average rates of change in every section are equalbecause the function is linear, its graph is a straight line,and the rate of change is just the slope of the graph.
What do you want me to do
For this case we have to:
Lewis carries 2 liters of water
Garret carries 1 liter of water
So, Lewis has 1 liter of water more than Garret.
By definition we have that 1 liter equals 1000 milliliters.
Thus, Lewis carries 1000 milliliters more water than Garret.
Answer:
1000 milliliters
Answer:
down below
Step-by-step explanation:
7/8:2 =0.4375
Answer:
B. Line c
Step-by-step explanation:
looking at the points, 3, -2 is on line c.
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