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Marysya12 [62]
3 years ago
5

What is the highest common factor of 65 and 56?

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
6 0
Highest common factor of 56&65 is 1
gizmo_the_mogwai [7]3 years ago
5 0

Step-by-step explanation:

don't you know how to do HCF

look for a number that can divide all the numbers

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Please help me it’s due today at 3:00pm will mark brainiest please help me please
tensa zangetsu [6.8K]

Answer: 83

Step-by-step explanation:

(88+92+87+x)/4 = 90

(277+x)/4 = 90

x+ 277 = 360

x = 83

5 0
3 years ago
Read 2 more answers
Find the value of each variable in the parallelogram
kompoz [17]

9514 1404 393

Answer:

  k = 7

  m = 8

Step-by-step explanation:

The diagonals bisect each other, so each half is equal to the opposite half.

  k +4 = 11 . . . . down-sloping diagonal

  k = 7

__

  m = 8 . . . . up-sloping diagonal

4 0
3 years ago
The probability of winning a particular game at the Game Place is 14 1/4 . Find the odds against winning the game.
Zinaida [17]
ANSWER

\frac{1}{3}



EXPLANATION

We want to find an odds ratio from a given probability, which is


\frac{1}{4}


We subtract the numerator 1 from the denominator 4 to obtain


4- 1= 3


The answer is the number of unfavorable outcomes. 

The Odds can then be expressed as

1 : 3


The ratio of favourable outcomes to unfavorable outcomes.


Or

\frac{1}{3}




6 0
3 years ago
A sector of a circle makes a 127° angle at its centre. If the arc of the sector has length 36 mm, find
Veseljchak [2.6K]

Answer:

Approximately 68.5\; \rm mm.

Step-by-step explanation:

Convert the angle of this sector to radians:

\begin{aligned}\theta &= 127^{\circ} \\ &= 127^{\circ} \times \frac{2\pi}{360^{\circ}} \\ &\approx 2.22\end{aligned}.

The formula s = r\, \theta relates the arc length s of a sector of angle \theta (in radians) to the radius r of this sector.

In this question, it is given that the arc length of this sector is s = 36\; \rm mm. It was found that \theta = 2.22 radians. Rearrange the equation s = r\, \theta to find the radius r of this sector:

\begin{aligned} r&= \frac{s}{\theta} \\ &\approx \frac{36\; \rm mm}{2.22} \\ &\approx 16.2\; \rm mm\end{aligned}.

The perimeter of this sector would be:

\begin{aligned}& 2\, r + s \\ =\; & 2 \times 16.2\; {\rm mm} + 36\; {\rm mm} \\ =\; & 68.5\; \rm mm\end{aligned}.

8 0
3 years ago
The area of a semicircle is A=1/2(3.14)r^2 solve for r
Inessa05 [86]
First divide bot sides of the formula by 1/2(3.14):-

2A / 3.14 =  r^2

r = sqrt (2A/3.14)
7 0
3 years ago
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