Lanzetta Elem. raised 5358....round to 5,000
Lantana Mid. Sch raised 2834....round to 3,000
Atlanta High Sch. raised 4132...round to 4,000
they need 14,000...they have (5,000 + 3,000 + 4,000) = 12,000....so they will need (14,000 - 12,000) = 2,000 more....keep in mind, these are estimates...not exact answers
Answer:
The number is 448.
Step-by-step explanation:
Hope it helps
You already have the right Answer which is b
Answer: The number of first-year residents she must survey to be 95% confident= 263
Step-by-step explanation:
When population standard deviation (
) is known and margin of error(E) is given, then the minimum sample size (n) is given by :-
, z* = Two-tailed critical value for the given confidence interval.
For 95% confidence level , z* = 1.96
As, = 8.265, E = 1
So, ![n= (\dfrac{1.96\times8.265}{1})^2 =(16.1994)^2\\\\= 262.42056036\approx263\ \ \ [\text{Rounded to the next integer}]](https://tex.z-dn.net/?f=n%3D%20%28%5Cdfrac%7B1.96%5Ctimes8.265%7D%7B1%7D%29%5E2%20%3D%2816.1994%29%5E2%5C%5C%5C%5C%3D%20262.42056036%5Capprox263%5C%20%5C%20%5C%20%5B%5Ctext%7BRounded%20to%20the%20next%20integer%7D%5D)
Hence, the number of first-year residents she must survey to be 95% confident= 263
