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3 years ago

How much energy will it take to increase the temperature of 200 milliliters if water by 12 degrees Celsius?

1 answer:

7 0

Answer: The specific heat capacity of water is 4,200 Joules per kilogram per degree Celsius (J/kg°C). This means that it takes 4,200 J to raise the temperature of 1 kg of water by 1°C. Lead will warm up and cool down fastest because it doesn't take much energy to change its temperature.

Explanation:

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Which of the following has the greatest momentum? *

denis-greek [22]

Answer:

Tortoise with a mass of 270 kg moving at a velocity of 0.5 m/s

Explanation:

From the question above,

(1) tortoise with a mass of 270 kg moving at a velocity of 0.5 m/s

Mometum = mass×velocity

Momentum = 270×0.5

Momentum = 135 kgm/s

(2) hare with a mass of 2.7 kg moving at a velocity of 7 m/s

Mementum = mass × velocity

Momentum = 2.7×7

Momentum = 18.9 kgm/s

(3) turtle with a mass of 91 kg moving at a velocity of 1.4 m/s

Momentum = mass × velocity

Momentum = 91×1.4

Momentum = 127.4 kgm/s

(4) roadrunner with a mass of 1.8 kg moving at a velocity of 6.7 m/s

Momentum = mass × velocity

Momentum = 1.8×6.7

Momentum = 12.06 kgm/s

From the above, the one with the greatest momentum is tortoise with a mass of 270 kg moving at a velocity of 0.5 m/s

3 0

2 years ago

A 1-mCi source of^60 Co is placed in the center of a cylindrical water-filled tank with an inside diameter of 20 cm and depth of

LenKa [72]

To solve this problem we need the concepts of Energy fluency and Intensity from chemical elements.

The energy fluency is given by the equation

$\Psi=4RcE\pi$

Where

$\Psi =$ The energy fluency

c = Activity of the source

r = distance

E = electric field

In the other hand we have the equation for current in materials, which is given by

$I= I_0 e^{-\mu_{h20}X_{h2o}} e^{-\mu_{Fe}X_{Fe}}$

Then replacing our values we have that

$I = 1*10^{-3} * 3.3*10^{10} * e ^{-0.06*1.1} e^{-0.058*7.861}$

$I = 1.3*10^7 Bq$

We can conclude in this part that 1.3*10^7Bq is the activity coming out of the cylinder.

Now the energy fluency would be,

$\Psi = \frac{cE}{4\pir^2}$

$\Psi = \frac{1.3*10^7*2*1.25}{4\pi*11^2}$

$\Psi = 2.14*10^4 MeV/cm^2.s$

The uncollided flux density at the outer surface of the tank nearest the source is $\Psi = 2.14*10^4 MeV/cm^2.s$

6 0

2 years ago

A wave amplitude 0.36m interferes with a second wave of amplitude 0.22m traveling in the same direction. What is the largest res

DerKrebs [107]

The largest resultant amplitude would be that created by constructive interference, basically when the two waves are of the same phase, so it would be 0.36m+0.22m= 0.58 m.

8 0

3 years ago

Select the correct answer.

Effectus [21]

A. logic, would be your answer i believe!

4 0

2 years ago

Refer to a long, straight wire carrying constant current I. What can be concluded about the magnitude of the magnetic field at d

sergij07 [2.7K]

Answer:

<em>"the magnitude of the magnetic field at a point of distance a around a wire, carrying a constant current I, is inversely proportional to the distance a of the wire from that point"</em>

Explanation:

The magnitude of the magnetic field from a long straight wire (A approximately a finite length of wire at least for close points around the wire.) decreases with distance from the wire. It does not follow the inverse square rule as is the electric field from a point charge. We can then say that<em> "the magnitude of the magnetic field at a point of distance a around a wire, carrying a constant current I, is inversely proportional to the distance a of the wire from that point"</em>

From the Biot-Savart rule,

B = μI/2πR

where B is the magnitude of the magnetic field

I is the current through the wire

μ is the permeability of free space or vacuum

R is the distance between the point and the wire, in this case is = a

5 0

2 years ago