3 years ago

Add the following displacement vectors: 12 m south and 15 m 55° E of N??

Physics

1 answer:

daser333 [38]3 years ago

4 0

12m S=0m E, -12m N
15m 55d E of N = 15 sin 55, 15 cos 55 N
Sum= (15sin55)m E, (-12 + 15 cos 55)m N

You might be interested in

What happens to light when it is shone through concave lenses? (1 point)

Nadusha1986 [10]

It would be a.,.,.,.,.

3 0

2 years ago

Read 2 more answers

if the Horse and Rider have a combined mass of 572 kg what force would be required to accelerate them 5 kph per second

Vlad [161]

Answer:

Force required to accelerate = 794.44 N

Explanation:

Force required = Mass of horse x Acceleration of horse

Mass of horse and rider, m= 572 kg

Acceleration of horse and rider, a = 5 kph per second

$=\frac{5*1000}{60*60} =1.39 m/s^2$

Force required = ma

= 572 x 1.39 = 794.44 N

Force required to accelerate = 794.44 N

8 0

3 years ago

Question 15 of 25

vichka [17]

Answer: conduction :it transfers heat between objects that are in direct contact with eachother

7 0

2 years ago

How many DAYS occur between a new moon and a first quarter moon?

N76 [4]

Answer:

About 29.5

Explanation:

4 0

2 years ago

Read 2 more answers

A guitar string is 0.620m long, and oscillates at 234Hz. What is the velocity of the waves in the string? m/s

9966 [12]

Answer:

v = 72.54 m/s

Explanation:

We have,

Length of a guitar string is 0.62 m

Frequency of a guitar string is 234 Hz

For guitar string,

$L=2\lambda\\\\\lambda=\dfrac{L}{2}\\\\\lambda=\dfrac{0.62}{2}\\\\\lambda=0.31\ m$

The velocity of the wave in the string is given by :

$v=f\lambda\\\\v=234\times 0.31\\\\v=72.54\ m/s$

So, the velocity of the waves in the string is 72.54 m/s.

3 0

3 years ago