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1 year ago

Heat is transferred from the sun-warmed surface of earth to the cooler overlying troposphere via _______

1 answer:

6 0

Heat is transferred from the sun-warmed surface of the earth to the cooler overlying troposphere via conduction.

<h3>Heat transfer from earth to atmosphere:</h3>

Conduction, convection, latent heating, and water phase transitions all help to carry heat from the Earth's surface, which has been warmed by the Sun, to the cooler troposphere above.

Latent heat flux is the worldwide transfer of latent heat energy via water and air currents. Here, we demonstrate how air circulation transports latent heat energy horizontally to cooler regions, where it condenses into rain or is deposited as snow, releasing the heat energy that was previously trapped there.

When air is heated from below by sunshine or by coming into contact with a warmer land or sea surface, convection occurs and the air below becomes less dense than the air above.

Learn more about Latent heat here:

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An elevator traveled 15 floors (150 ft) at a speed of 4.5 m/s. What additional information is needed to determine the velocity o

vladimir2022 [97]

Answer:

Velocity is vector quantity.So it needs direction in addition to speed.

Explanation:

The velocity of an object is the rate of change of its position with respect to a frame of reference, and is a function of time. Velocity is equivalent to a specification of its speed and direction of motion.

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2 years ago

A 50.0 kg crate is pulled 375 N of force applied to a rope. The crate slides without friction.

LUCKY_DIMON [66]

Hi there!

We can use the work-energy theorem to solve.

Recall that:

$\large\boxed{W = \Delta KE = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2}$

The initial kinetic energy is 0 J because the crate begins from rest, so we can plug in the given values for mass and final velocity:

$W = \frac{1}{2}(50)(5.61^2) = 786.8025 J$

Now, we can define work:

$\large\boxed{W = Fdcos\theta}}$

Now, plug in the values:

$786.8025 = Fdcos\theta\\\\786.8025 = (375)(3.07)cos\theta$

Solve for theta:

$cos\theta = .6834\\\theta = cos^{-1}(.6834) = \boxed{46.887^o}$

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2 years ago

What relationship exists between the amplitude of a wave and amount of disturbance in the water?

guapka [62]

A wave is a result of the disturbance in the equilibrium state. There are two types of wave, transverse and longitudinal. Transverse wave affects amplitude while longitudinal wave affects the frequency of the wave. As for the transverse wave, the magnitude of the perpendicular disturbance of the wave is directly proportional to the amplitude of the wave. The higher the transverse disturbance the higher the amplitude.

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2 years ago

Help with physics homework

bogdanovich [222]

What is the question is it some type of science thing

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3 years ago

What do you call the energy from earthquakes that propagate through earth as vibrations?

svet-max [94.6K]

Answer:elastic energy i believe

Explanation:

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2 years ago