Answer:
The recombination frequency between two genes exhibits a positive correlation with the distance between them, that is, farther they are, and more will be the chance of recombination. Thus, recombination frequency is used to signify distance among the two genes, for example, 1 percent recombination frequency demonstrates distance of 1 map unit.
Let us consider that the heterozygous female of genotype AaBb can generate four kinds of gametes, that is, AB, Ab, aB and ab. Of these, the two gametes are the outcomes of recombination, or it can be said that 50 percent are recombinants. Thus, it can be concluded that in case of two linked genes, the maximum probable recombination frequency is 50 percent.
This shows that any genes, which are distant than 50 map units will function as unlinked and will function as if they were on distinct chromosomes, and the frequency of recombinant frequency will be 50 percent.
In the given question, it is given that the map distance between the two genes is 80 map units, that is, more than 50 map units. The maximum probable recombinant offspring will be 50 percent of the entire offspring.
Answer:
I believe it is B, direct contact
Explanation:
Ali most likely wasn't eating food that the dog had contaminated, nor was it likely that a mosquito first bit the dog and then Ali. This leaves A and D, and A seems to be more likely.
Apologies if I am incorrect.
I believe the answer is: Different scientists use different data for investigation.
I say that because different scientists have different equipment, ideas, and have different methods. I hope I was right and i hope it helped and i wasn't to late to answer this question.
Urban sprawl..............
Most
doctors and midwives recommend waiting at least four to six weeks
after birth to have intercourse.
<span>This
time window ensures that the cervix close, postpartum bleeding stop,
and any internal injures heal properly so the woman don’t have any
risk of hemorrhage or infection.</span>
