The diagonal fencing will be the hypotenuse of a right triangle with sides 120yds long so:
h=√2(120^2))
h=√28800 yd
And the surrounding fencing will just be four times the side length of 120yds so:
s=480yd
So the total fencing needed is:
f=480+√28800 yards
f≈649.71 yd (to nearest hundredth of a yard) which is
f≈650 yds (to nearest whole yard)
But, I wasn't sure, if they just want the diagonal fencing needed then it is just:
f=√28800
f≈170 yds (to nearest yard)
Answer:
11m-3v
Step-by-step explanation:
Answer:
2, 4, 6, 8 , 10
Step-by-step explanation:
Answer:
1st, 3rd, and 4th box.
Step-by-step explanation:
9^5=59049
9^2=81 9^3=729 729*81=59049 yes
9^5=59049 59049x9=531441 no
9^4=6561 6561*9=59049 yes
9^2=81 81x81=6561 6561*9=59049 yes
9^3=729 729x729=531441 no
