This problem can be solved using a kinematic equation. For this case, the following equation is useful:
v_final = v_initial + at
where,
v_final = final velocity of the nail
v_initial = initial velocity of the nail
a = acceleration due to gravity = 9.8 m/s^2
t = time
First, we determine the time it takes for the nail to hit the ground. We know that the initial velocity is 0 m/s since the nail was only dropped. It has a final velocity of 26 m/s. We substitute these values to the equation and solve for t:
26 = 0 + 9.8*t
t = 26/9.8 = 2.6531 s
The problem asks the velocity of the nail at t = 1 second. We then subtract 1 second from the total time 2.6531 with v_final as unknown.
v_final = 0 + 9.8(2.6531-1) = 16.2004 m/s.
Thus, the nail was traveling at a speed of 16. 2004 m/s, 1 second before it hit the ground.
In order to be electrically neutral, an atom has to contain
equal numbers of protons (with their positive charges) and
electrons (with their negative charges).
Answer:
Be sure to unplug the power source of all electrical equipment before working on it. Always pull from the plug, not the cord. Always wear proper non conductive clothing – insulated gloves, non conductive protective apparel and shoes with insulated soles. Avoid loose clothing or ties.
Answer:
T=+1.133N
Explanation:
Tension and weight are forces that have opposite directions
Weight is negative (downward)
W=m*g= 0.11kg*(-9.8m/s^2)
W= -1.078N
Tension is possitive (upward)
The total force will be the sum of both (the difference taking in consideration the direction)
Ft= T+W
Also the total force is the product of the mass due to acceleration:
Ft=m*a
Ft= +0.11kg*0.5m/s^2
Ft=+0.055N (upward)
Tension will be the difference between Ft and W:
T= Ft-W
T=+0.055N-(-1.078N)
T=+1.133N
I believe the answer is option C 1.8 kg•m/s to the east