<span>Condensation is the change of
the substance from liquid to solid phase. Example of this is the formation of
ice. Vaporization is the change of substance from liquid to gas phase. Example of
this is the boiling of water. Deposition is the change of a substance from gas
to solid phase. Example of this is the formation of ice on a winter day. Sublimation
is the change of a substance from solid to gas phase. Example of this is dry
ice. The answer is letter C.</span>
satellite originally moves in a circular orbit of radius R around the Earth. Suppose it is moved into a circular orbit of radius 4R.
(i) What does the force exerted on the satellite then become?
eight times larger<span>four times larger </span>one-half as largeone-eighth as largeone-sixteenth as large(ii) What happens to the satellite's speed?<span>eight times larger<span>four times larger </span>one-half as largeone-eighth as largeone-sixteenth as large(iii) What happens to its period?<span>eight times larger<span>four times larger </span>one-half as largeone-eighth as largeone-sixteenth as large</span></span>
<span>
</span>
Answer: 14.7kJ, 29.4kJ, 44.1kJ
Explanation:
<em>The gravitational potential energy is the energy that a body or object possesses, due to its position in a gravitational field. </em>
<em />
In the case of the Earth, in which the gravitational field is considered constant, the value of the gravitational potential energy 
will be:
Where 
is the mass of the object, 
the acceleration due gravity and 
the height of the object.
Knowing this, let's begin with the calculaations:
For m=3kg
For m=6kg
For m=9kg
Answer:
Explanation:
Force Mass * acceleration
F = ma
a = F/m
Sum of force = 16.3N - 15.8N = 0.5N
Mass = 0.62kg
Substitute
a = 0.5/ * 0.62
a = 0.81m/s²
The acceleration of the toy is 0.81m/s²
Answer:
Explanation:
1 )
Here
wave length used that is λ = 580 nm
=580 x 10⁻⁹
distance between slit d = .46 mm
= .46 x 10⁻³
Angular position of first order interference maxima
= λ / d radian
= 580 x 10⁻⁹ / .46 x 10⁻³
= 0.126 x 10⁻² radian
2 )
Angular position of second order interference maxima
2 x 0.126 x 10⁻² radian
= 0.252 x 10⁻² radian
3 )
For intensity distribution the formula is
I = I₀ cos²δ/2 ( δ is phase difference of two lights.
For angular position of θ1
δ = .126 x 10⁻² radian
I = I₀ cos².126x 10⁻²/2
= I₀ X .998
For angular position of θ2
I = I₀ cos².126x2x 10⁻²/2
= I₀ cos².126x 10⁻²
