You are trying to remove small particles from water. What would be the BEST thing you could do to remove the small particles? *

You are given two infinite, parallel wires each carrying current I. The wires are separated by a distance d, and the current in

hoa [83]

Answer:F/L = μ0*I²/2πd

Explanation:

Both wires carries current of the value (I) and are separated by the distance (d).

The length of both wires is (L).

The first wire creates a magnetic field of the magnitude according to Bio-savart law

B=(Uo * I)/2πd

This magnetic field has the ability to exert a force F on the second wire.

This force (F) is given as

F=BIL* sin θ

θ here is 90 because the magnetic field is perpendicular to the length of the second wire.

Thus the value of sin 90 = 1

Hence F= BIL

But B=(Uo * I)/2πd.

We have that F= B=[(Uo * I)/2πd] x IL

Thus we have that F= [Uo* I²/2πd] x L

By rearranging, and bringing L to the left hand side of the equation, we have that

F/L = [Uo* I²/2πd]

6 0

3 years ago

A convex thin lens with refractive index of 1.50 has a focal length of 30cm in air. When immersed in a certain transparent liqui

GalinKa [24]

Answer:

$n_l = 1.97$

Explanation:

given data:

refractive index of lens 1.50

focal length in air is 30 cm

focal length in water is -188 cm

Focal length of lens is given as

$\frac{1}{f} =\frac{n_2 -n_1}{n_1} * \left [\frac{1}{r1} -\frac{1}{r2} \right ]$

$\frac{1}{f} =\frac{n_{g} -n_{air}}{n_{air}} * \left [\frac{1}{r1} -\frac{1}{r2} \right ]$

$\frac{1}{f} =\frac{n_{g} -1}{1} * \left [\frac{1}{r1} -\frac{1}{r2} \right ]$

focal length of lens in liquid is

$\frac{1}{f} =\frac{n_{g} -n_{l}}{n_{l}} * \left [\frac{1}{r1} -\frac{1}{r2} \right ]$

$=\frac{n_{g} -n_{l}}{n_{l}} [\frac{1}{(n_{g} - 1) f}$

rearrange fro $n_l$

$n_l = \frac{n_g f_l}{f_l+f(n_g-1)}$

$n_l = \frac{1.50*(-188)}{-188 + 30(1.50 -1)}$

$n_l = 1.97$

7 0

3 years ago

Part A A supernova that occurs 10,000 years from now in a galaxy 50,000 light years away: A supernova that occurs 10,000 years f

melisa1 [442]

The Supernova will be observed on Earth 60,000 years from now.

<h3>What is Supernova?</h3>

A supernova is a star's tremendous and brilliant explosion. It is referred to as a supernova or a supernovae and is abbreviated as SN or SNe.
This fleeting astronomical occurrence takes place either when a white dwarf is set off into uncontrolled nuclear fusion or during the latter phases of the development of a big star. The original object, known as the progenitor, either disintegrates completely or falls into a neutron star or black hole.
Before fading over the course of several weeks or months, the peak optical luminosity of a supernova can be similar to that of an entire galaxy.
Compared to novae, supernovae are more energetic. Nova, which in Latin means "new," refers to what appears to be a transitory new bright star in astronomy. Supernovae can be distinguished from regular novae by the prefix "super-."

To learn more about Supernova with the given link

brainly.com/question/12702138

#SPJ4

6 0

2 years ago

How much force is needed to accelerate a 5-kg object at 4 m/s2

Alecsey [184]

F = m · a (Newton's 2nd law of motion)

F = (5 kg) · (4 m/s )

<em>F = 20 Newtons</em>

7 0

4 years ago

um can someone please help me I'm really stuck on this question and an explanation would be nice thank you

masha68 [24]

Answer: A wavelength is how long ONE wave is. First divide the distance of the whole diagram by the number of waves. you will get 2m. This is the answer.

6 0

3 years ago