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lukranit [14]
3 years ago
8

A water-skier with weight Fg = mg moves to the right with acceleration a. A horizontal tension force T is exerted on the skier b

y the rope, and a horizontal drag forcc Fa is cxertcd by thc watcr on the ski. The water also exerts a vertical lift force L on the skier. Which of the following are correct relationships between the forces exerted on the skier-ski system? Select two answers. (A) T-Fd = ma (B) L-Fg=ma (C) L- =0 (D) T- Fd 0
Physics
1 answer:
Degger [83]3 years ago
3 0

Answer:

The correct relationships are T-fg=ma and L-fg=0.

(A) and (C) is correct option.

Explanation:

Given that,

Weight Fg = mg

Acceleration = a

Tension = T

Drag force = Fa

Vertical force = L

We need to find the correct relationships

Using balance equation

In horizontally,

The acceleration is a

T-Fd=ma...(I)

In vertically,

No acceleration

w=L

mg-L=0

Put the value of mg

L-fg=0....(II)

Hence,  The correct relationships are T-fg=ma and L-fg=0.

(A) and (C) is correct option.

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3 years ago
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We want to see how the time will be affected 
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Multiply each side by  2 :         2 D  =            g    t²  

Divide each side by ' g ' :      2 D/g =                  t² 

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Looking at the equation now, we can see what happens to ' t ' when only ' g ' changes:

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Gravity on the surface of the moon is roughly  1/6  the value of gravity on the surface of the Earth.

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AVprozaik [17]
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