First Find moles of LiOH (.235 moles/L X .01673L) You have .00423269 moles of LiOH. The Equation is written (HBr +LiOH -> LiBr + H2O), 1;1 Ratio. We find the molarity of HBr (.00423269 moles / .01 L). We are left with .42M HBr.
Soak into the ground as groundwater. This is capped infiltration.
Answer:
The answer to your question is below: 8 electron in its outer most shell.
Explanation:
Argon like noble gases are stable elements that means that they do not react with other elements. They have eight electrons in their outermost shell; Elements are stable when they reach 8 electronsin their outer most shell, some elements reach 8 electrons receiving from others (nonmetals) and others donate electrons ( metals).
Answer:
Explanation:
No, it is preposterous and possible to expect or to disengage and isolate a basic and neutral compound by 1M NaOH in DCM. Since neutral compounds do not react with NaOH, and NaOH itself is a base so it can't react with another base to yield salt. For that reason, we just need a corrosive element i.e an acid.
So; In DCM, we can't utilize 1M NaOH rather than 1M HCI for isolation and detachment of neutral and basic compounds.