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TEA [102]
3 years ago
7

Brainliest plsss i need help

Mathematics
1 answer:
lesantik [10]3 years ago
5 0

Answer:

I believe it is A

Step-by-step explanation:

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The sum of two numbers is 67 and the difference is 13 . What are the numbers?
svet-max [94.6K]

Answer:

27 and 40

Step-by-step explanation:


3 0
3 years ago
The figures are similar. Give the ratio of the perimeters and the ratio of the areas of the first figure to the second.
pickupchik [31]

Answer: first option.

Step-by-step explanation:

The ratio of the area of the triangles can be calculated as following:

ratio_{(area)}=(\frac{l_1}{l_2})^2

Where l_1 is the lenght of the given side of the smaller triangle and l_2 is the lenght of the given side of the larger triangle.

Therefore:

ratio_{(area)}=(\frac{28}{32})^2=\frac{49}{64}

It can be written as following:

ratio_{(area)}=49:64

The ratio of the perimeter is:

ratio_{(perimeter)}=\frac{l_1}{l_2}

Where l_1 is the lenght of the given side of the smaller triangle and l_2 is the lenght of the given side of the larger triangle.

Therefore:

ratio_{(perimeter)}=\frac{28}{32}=\frac{7}{8}

It can be written as following:

ratio_{(perimeter)}=7:8

5 0
3 years ago
SIMPLE HELP HELP HELP PLEASE ONLY 1 ANSWER NONE OF THE ABOVE OR ALL IS NOT THE ANSWER SO PLEASE DO IT RIGHT THIS TIME WILL GIVE
Eva8 [605]

Answer:

A

The first option is the correct!

They are parallel so they never connect! :)

Photos attached!

Hope this helps! Have a great day! :)

7 0
3 years ago
Read 2 more answers
The sum of 6 consecutive integers is 270. What is the second number in the sequence?
Rina8888 [55]
N+(n+1)+(n+2)+(n+3)+(n+4)+(n+5)=270
We use these terms to represent the first six consecutive integers in the sequence
Now we group like terms:
6n+15=270
Minus 15 from both sides of the equation
6n=255
n=42.5 which is not an integer
Is this a joke question?
Besides that, the 2nd number will be 43.5
3 0
3 years ago
*Silly and/or spam answers will not be tolerated*
stepladder [879]

Answer:

-1/8

Step-by-step explanation:

lim x approaches -6     (sqrt( 10-x) -4) / (x+6)

Rationalize

   (sqrt( 10-x) -4)      (sqrt( 10-x) +4)

    ------------------- * -------------------

       (x+6)                 (sqrt( 10-x) +4)

We know ( a-b) (a+b) = a^2 -b^2

a= ( sqrt(10-x)   b = 4    

(10-x) -16

-------------------

(x+6) (sqrt( 10-x) +4)    

-6-x

-------------------

(x+6) (sqrt( 10-x) +4)

Factor out -1 from the numerator

-1( x+6)

-------------------

(x+6) (sqrt( 10-x) +4)

Cancel x+6 from the numerator and denominator

-1

-------------------

(sqrt( 10-x) +4)

Now take the limit

lim x approaches -6    -1/ (sqrt( 10-x) +4)

                                      -1/ (sqrt( 10- -6) +4)

                                      -1/ (sqrt(16) +4)

                                      -1 /( 4+4)

                                        -1/8

5 0
3 years ago
Read 2 more answers
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