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The value of h(t) when is 10.02.
Solution:
Given function
To find the value of h(t) when :
Substitute in the given function.
Now multiply the common terms into inside the bracket.
Now, in the first term, the numerator and denominator both have common factor 16. So reduce the first term into the lowest term.
To make the denominator same, take LCM of the denominators.
LCM of 64 and 32 = 64
= 10.02
Hence the value of h(t) when is 10.02.
Answer:
x = -2.5
x = 2
Step-by-step explanation:
Hello!
We can remove the denominators by multiplying everything by it.
Solve:
Let's make one side equal to 0.
Solve by factoring, and then the zero product property.
Multiply 2 and -10. You get -20. Think of two number that multiply to -20, and add to 1. If we think about the standard form of a quadratic, , think two numbers that equal "ac" and add up to "b".
Using the zero product property, set each factor to 0 and solve for x.
- 2x + 5 = 0
2x = -5
x = -5/2 = -2.5 - x - 2 = 0
x = 2
The two answers are x = -2.5, and x = 2.