Hi There! :)
<span>What 5x23p9x2 and what is the common number?
5</span>×23=115
<span>115</span>×9=1035
<span>1035</span>×2=2070
<span>
Therefore 2070 is the answer
</span>
Answer:
third one is a required answer.
x =2y
or
1/x=y
Make bottom numbers same
find least common multipules of 8,12,4 and 3
8=2 times 2 times 2
12=2 times 2 times 3
4=2 times 2
3=3
lcm=2 times 2 times 2 times 3=24
5/8 times 3/3=15/24
5/12 times 2/2=10/24
3/1 times 24/24=72/24
1/4 times 6/6=6/24
2/3 times 8/8=16/24
we now have
15/24-10/24(72/24-6/24)+16/24
pemdas
simplify parenthasees first
72/24-6/24=66/24
now we have
15/24-10/24(66/24)+16/24
multiply
15/24-660/576+16/24
make same bottom number
15/24 times 24/24=360/576
16/24 times 24/24=384/576
360/576-660/576+384/576
84/576
7/48
answer is 7/48
Answer:
The percentle for Abby's score was the 89.62nd percentile.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation(which is the square root of the variance)
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Abby's mom score:
93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the scores was 9604.
93rd percentile. X when Z has a pvalue of 0.93. So X when Z = 1.476.

So




Abby's score
She scored 648.

So



has a pvalue of 0.8962.
The percentle for Abby's score was the 89.62nd percentile.
Answer:
Option (a) is correct.
The system of equation becomes

Step-by-step explanation:
Given : Equation 
We have to construct a system of equations that can be used to find the roots of the equation 
Consider the given equation 
To construct a system of equation put both sides of the given equation equal to a same variable.
Let the variable be "y", Then the equation 
becomes,
Thus, The system of equation becomes

Option (a) is correct.