3 years ago

which polynomials are in standard form? A. t^4-1 B. -2t^2+3t+4 C. 4t-7 D. None of The Above Choose all answers that apply

1 answer:

5 0

Answer:

B. -2t^2+3t+4

Step-by-step explanation:

The standard form as

ax^2 + bx + c

Option B meets that requirement, even though it has a '-' in front

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ryzh [129]

Answer: $f(x)=5x^2-4x+5$

Step-by-step explanation:

A quadratic function is as following; $ax^2+bx+c$

Notice that it cannot be $f(x)=0x^2-4x+7$ because if you solve; $0x^2=0$ which eliminates the $x^2$ .

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Volgvan

The answer is 2,-5 you put the points are in the same spot just rotated

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Studentka2010 [4]

E is exponents, D is division, A is addition

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Vesna [10]

$(2^8 \times 5^{-5} \times 19^0)^{-2} \times (\dfrac{5^{-2}}{2^3})^4 \times 2^{28} =$

$= 2^{-16} \times 5^{10} \times 1 \times \dfrac{5^{-8}}{2^{12}} \times 2^{28}$

$= 2^{-16} \times 5^{10} \times 5^{-8} \times 2^{-12} \times 2^{28}$

$= 2^{-16} \times 2^{-12} \times 2^{28} \times 5^{10} \times 5^{-8}$

$= 2^{-16-12+28} \times 5^{10-8}$

$= 2^{0} \times 5^{2}$

$= 1 \times 25$

$= 25$

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babymother [125]

I do not answer I mean College and I passed it

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