Let f(x)=y
f^-1(x)=x
y=1/(x+5) - 1
y+1=1/(x+5)
(x+5)=1/(y+1)
x=1/(y+1)-5
f^-1(x)=1/(x+1) -5
denominator cannot equals to zero
x+1≠0
x≠-1
answer
B
Answer:
1 ± i(1/2)√2
Step-by-step explanation:
Write this quadratic in standard form: subtract 3 from both sides. This results in 2x^2 - 4x - 3 = 0. Let's apply the quadratic formula. The coefficients of the x terms are 2, -4 and -3, so the discriminant is (-4)^2 - 4(2)(-3), or 16 - 24 = -8.
Following the format of the quadratic formula, we get
-(-4) ±i2√8 4 ±i2√2
x = ----------------- = --------------- = 1 ± i(1/2)√2
4 4
The magnitude of the resultant vector is 27 miles
<h3>How to determine the vector magnitude</h3>
Resultant vector = Distance of A - Distance of B
This is so because of the opposite direction of the car's movement
A = 87 miles
B = 114 miles
Resultant vector = 114 - 87
Resultant vector = 27 miles
Thus, the magnitude of the resultant vector is 27 miles
Learn more about resultant vector here:
brainly.com/question/3184914
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1 is the given at the top of the question and the reasoning is bec it’s given
