Question

Two particles, with identical positive charges and a separation of 2.65 10-2 m, are released from rest. Immediately after the release, particle 1 has an acceleration 1 whose magnitude is 5.00 103 m/s2, while particle 2 has an acceleration 2 whose magnitude is 7.70 103 m/s2. Particle 1 has a mass of 6.20 10-6 kg. (a) Find the charge on each particle. q1 = C q2 = C (b) Find the mass of particle 2. kg

Answer 1

Answer:

a)  $q=4.92*10^{-8} C$

b)  $m=4.026*10^{-6} kg$

Explanation:

From the question we are told that:

Separation distance $d=2.65*10^{-2} m$

Acceleration 1 $a_1=5.00*10^3 m/s^2,$

Acceleration 2 $a_2=7.70*10^3 m/s^2,$

Mass 1 $m_1=6.20*10^{-6}$

Generally the equation for Force is mathematically given by

 $F=ma$

For Particle 1

 $F=6.2*10^{-6} *5*10^3$

 $F=0.031 N$

Also

 $F=\frac{kq_1*q2}{r^2}$

Where

 $q_1=q_2$

Therefore

 $0.031=\frac{9*10^9*q^2}{(2.65*10^-2)^2}$

 $q=4.92*10^{-8} C$

b)

Generally the equation for Force is mathematically given by

 $F=ma$

 $0.031=7.7*10^3$

 $m=4.026*10^{-6} kg$