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Vladimir79 [104]
3 years ago
6

Explain how a plant is adapted for photosynthesis

Chemistry
1 answer:
snow_lady [41]3 years ago
4 0

Answer:

the utencils of a plant is called photosynthesis and your wc

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Each liter of air has a mass of 1.80 grams. How many liters of air are contained in
natita [175]

Question:

Each liter of air has a mass of 1.80 grams. How many liters of air are contained in 2.5 x103) kg of air?

Answer:

11.48106 L

5 0
3 years ago
Saponification is a chemical reaction _____. A. due to the presence of a strong organic acid. B. that results in an alcohol and
dezoksy [38]

Answer:

that results in an alcohol and a carboxylic acid.

Explanation:

Saponification is a chemical reaction process of alkaline hydrolysis of esters(R'COOR group) by which soap is obtained.

For Example, when a base such as sodium hydroxide [NaOH]  is used to hydrolyze an ester, the products are a carboxylate salt and an alcohol. Because soaps are prepared by the alkaline hydrolysis of fats and oils.

In a saponification reaction, alkaline hydrolysis of fats and oils with sodium hydroxide  yields propane-1,2,3-triol and the corresponding sodium salts of the component fatty acids.

i.e  Fat or oil + caustic alkali ⇒ Soap + propane-1,2,3-triol

As a specific example, ethyl acetate and NaOH react to form sodium acetate and ethanol:

The reaction goes to completion in the image below:

8 0
3 years ago
What is the oxidation number of oxygen in OF2
Serga [27]
Oxygen almost always has an oxidation number of -2

The only exception is in H2O2 which makes it -1, and in OF2 which makes it +2
3 0
3 years ago
Read 2 more answers
When heated, KClO3 decomposes into KCl and O2. 2KClO3⟶2KCl+3O2 If this reaction produced 13.2 g KCl, how many grams of O2 were p
MissTica

Answer:

8.5gm O2 produced

Explanation:

When heated, KClO3 decomposes into KCl and O2. 2KClO3⟶2KCl+3O2 If this reaction produced 13.2 g KCl, how many grams of O2 were produced?

for every 2 moles of KCl produced, 3 moles of O2 are produced

Mol weight of KCl =39+35.5=74.5gm

13.2 gm KCl = 13.2/74.5 = 0.177 moles

this will make (3/2) X 0.177 = 0.2655 moles of O2

O2 mol wt is 32  0.2655 X32 = 8.5gm O2 produced

7 0
2 years ago
What are the laws and calculations governing gas behavior?
Thepotemich [5.8K]

Answer:

Laws governing gas behavior.

Explanation:

Boyle's law:

It relates the pressure and volume of an ideal gas at a constant temperature.

According to this law:

"The volume of a fixed amount of gas at constant temperature is inversely proportional to its pressure".

P  \alpha   V.

Charle's law:

It relates the volume and absolute temperature of an ideal gas at a constant pressure.

According to this law:

"The volume of a fixed amount of gas at constant pressure is directly proportional to its absolute temperature".

V   \alpha   T.

Avogadro's law:

According to this law:

equal volumes of all gases under the same conditions of temperature and pressure contain, an equal number of moles.

V   \alpha    n.

Ideal gas equation:

By combining all the above-stated gas laws, this equation is formed as shown below:

V  \alpha   \frac{nT}{P} \\=> V= R. nT/ P\\=>PV=nRT

R is called universal gas constant.

It has a value of 0.0821L.atm.mol-1.K-1.

8 0
3 years ago
Read 2 more answers
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