Answer: chemical substance
Explanation:
<span>0.0797 g
Looking at the formula, 1 mole of KIO3 and 5 moles of KI will react and produce moles of iodine molecules or 6 moles of iodine atoms. So first, determine the number of moles of KIO3 and KI provided
moles KIO3 = 0.0121 * 0.097 = 0.0011737 mol
moles KI = 0.0308 * 0.017 = 0.0005236 mol
The limiting reactant is KI at 0.0005236 mol so divide by 5 and multiply by 6 to get the number of moles of iodine atoms.
0.0005236 / 5 * 6 = 0.00062832 mol
Lookup the atomic weight of iodine which is 126.90447
And multiply that by the number of moles of iodine produced
126.90447 g/mol * 0.00062832 mol = 0.079736617 g
Rounding to 4 decimal places gives 0.0797 g</span>
Answer:
Reactants: 6 molecules of carbon (iv) oxide and 6 molecules of water
Products: 1 molecule of glucose with 6 molecules of oxygen
Explanation:
Reactants: the left-hand side; and
Products: Right hand side
a)
26C5 -> 26 choices of 5 things
b)
15C1 × 11C4
c)
11C1 × 15C4
d)
11C2 × 15C2
e)
11C4
or
15C4
