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4 years ago

Which of the following is a form of potential energy

Chemistry

2 answers:

Vedmedyk [2.9K]4 years ago

8 0

Answer:

Its nuclear energy

Explanation:

Its D

igor_vitrenko [27]4 years ago

6 0

It’s D) nuclear energy

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Compare the solubility of silver chromate in each of the following aqueous solutions: Clear All 0.10 M AgCH3COO 0.10 M Na2CrO4 0

slavikrds [6]

Solution :

Comparing the solubility of silver chromate for the solutions :

$0.10 \ M \ AgCH_3COO$ ----- Less soluble than in pure water.

$0.10 \ M \ Na_2CrO_4$ ----- Less soluble than in pure water.

$0.10 \ M \ NH_4NO_3$ ----- Similar solubility as in the pure water

$0.10 \ M \ KCH_3COO$ ----- Similar solubility as in the pure water

The silver chromate dissociates to form :

$AgCrO_4 (s) \rightleftharpoons 2Ag^+ (aq) +CrO_4^{2-}(aq)$

When 0.1 M of $AgCH_3COO^-$ is added, the equilibrium shifts towards the reverse direction due to the common ion effect of $Ag^+$ , so the solubility of $Ag_2CrO_4$ decreases.

Both $AgCH_3COO$ and $KCH_3COO$ are neutral mediums, so they do not affect the solubility.

4 0

3 years ago

There are 5,280 feet in 1 mile. How many inches are in 2 miles? A) 10,560

hoa [83]

Answer:

126,720 inches

Explanation:

4 0

3 years ago

Write the definition of a compound and give two examples

QveST [7]

Answer:

a thing that is composed of two or more separate elements ex. Acid and Water

3 0

3 years ago

Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 Pb(ClO3)2 with aqueous NaI . NaI. Include phases. chemica

FinnZ [79.3K]

Answer: The mass of precipitate (lead (II) iodide) that will form is 119.89 grams

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of NaI solution = 0.130 M

Volume of solution = 0.400 L

Putting values in above equation, we get:

$0.130M=\frac{\text{Moles of NaI}}{0.400L}\\\\\text{Moles of NaI}=(0.130mol/L\times 0.400L)=0.52mol$

The balanced chemical equation for the reaction of lead chlorate and sodium iodide follows:

$Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)$

The precipitate (insoluble salt) formed is lead (II) iodide

By Stoichiometry of the reaction:

2 moles of NaI produces 1 mole of lead (II) iodide

So, 0.52 moles of NaI will produce = $\frac{1}{2}\times 0.52=0.26mol$ of lead (II) iodide

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of lead (II) iodide = 0.26 moles

Molar mass of lead (II) iodide = 461.1 g/mol

Putting values in above equation, we get:

$0.26mol=\frac{\text{Mass of lead (II) iodide}}{461.1g/mol}\\\\\text{Mass of lead (II) iodide}=(0.26mol\times 461.1g/mol)=119.89g$

Hence, the mass of precipitate (lead (II) iodide) that will form is 119.89 grams

4 0

3 years ago

Which of the following is a hypothesis for an experiment measuring solubility of sodium sulfate?

SCORPION-xisa [38]

A would be a hypothesis

7 0

3 years ago