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sattari [20]
4 years ago
15

Which of the following is a form of potential energy

Chemistry
2 answers:
Vedmedyk [2.9K]4 years ago
8 0

Answer:

Its nuclear energy

Explanation:

Its D

igor_vitrenko [27]4 years ago
6 0
It’s D) nuclear energy
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I need help is it A B or C second Trimester B First Trimester or C Third Trimester?
SOVA2 [1]

Answer:

A

Explanation:

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5 0
3 years ago
Elements can be described by various properties, and identified by their boiling and melting points. For example, gold melts at
Leni [432]

Answer:

Elements can be described by various properties, and identified by their boiling and melting points. For example, gold melts at

Elements can be described by various properties, and identified by their boiling and melting points. For example, gold melts at 1,064ºC and boils at 2,856ºC. Does boiling point depend on the mass present?

A. No; chemical properties stay the same regardless of mass.

B. No; physical properties stay the same regardless of mass.

C. Yes; physical properties can change when mass increases or decreases.

D. No; qualitative properties like boiling point stay the same regardless of mass.

Explanation:

3 0
2 years ago
What's the definition if blood
ANEK [815]
Blood is a liquid substance flowing through the arteries and veins of the body. In a healthy normal person, approximately 45% of their blood volume are cells (mostly red blood cells, white blood cells and platelets).

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8 0
3 years ago
calculate the volume occupied by 10g of propane gas, under normal conditions of temperature and pressure
andriy [413]

Answer:

5.5 L

Explanation:

First we <u>convert 10 g of propane gas</u> (C₃H₈) to moles, using its <em>molar mass</em>:

  • 10 g ÷ 44 g/mol = 0.23 mol

Then we <u>use the PV=nRT formula</u>, where:

  • P = 1 atm & T = 293 K (This are normal conditions of T and P)
  • n = 0.23 mol
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • V = ?

1 atm * V = 0.23 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 293 K

  • V = 5.5 L
3 0
3 years ago
A buffer solution is composed of 4.00 4.00 mol of acid and 3.25 3.25 mol of the conjugate base. If the p K a pKa of the acid is
Reika [66]

<u>Answer:</u> The pH of the buffer is 4.61

<u>Explanation:</u>

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[\text{conjuagate base}]}{[\text{acid}]})

We are given:

pK_a = negative logarithm of acid dissociation constant of weak acid = 4.70

[\text{conjuagate base}]} = moles of conjugate base = 3.25 moles

[\text{acid}]  = Moles of acid = 4.00 moles

pH = ?

Putting values in above equation, we get:

pH=4.70+\log(\frac{3.25}{4.00})\\\\pH=4.61

Hence, the pH of the buffer is 4.61

8 0
3 years ago
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