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Kruka [31]
2 years ago
13

A pair of pants was on sale for 40% off. The sale price of the pants was $18.00. What was the original price of the pants?

Mathematics
1 answer:
iragen [17]2 years ago
5 0

Answer:

The original price of the pants was $30.

Step-by-step explanation:

Let x be equal to the original price of the pants.

Because the pants are 40% off, their final price was 60% of the original price. 60% as a decimal is 0.6. Using this information, we can set up the following equation and solve:

0.6x=18

Divide both sides by 0.6

0.6x/0.6=18/0.6

x=30

I hope this helps!

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Answer:

Option d) The rocket was above 300 feet for approximately 2 seconds.

Explanation:

The rocket was above 300 for both 2 and 4 seconds.

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ASHA 777 [7]
Median, upper quartile, and maximum are all incorrect
5 0
3 years ago
If b is the midpoint of AC, which of the following choices is the value of x?
katrin [286]
If B is the midpoint of AC, that means that the distances from A to B and B to C are the same. The distance from A to B is 8x + 4, and the distance from B to C is 10x - 6, so we can set these two equivalent:

8x + 4 = 10x - 6

Solving for x:

4 = 2x - 6 (subtract 8x from both sides)
10 = 2x (add 6 to both sides)
5 = x (divide both sides by 2)

So, x = 5, which is the second option given.
8 0
3 years ago
Find the value of 5x-6 given that 2x-7=9​
erik [133]

Answer:

34

Step-by-step explanation:

Given that

2x - 7 = 9 ← solve for x

Add 7 to both sides

2x = 16 ( divide both sides by 2 )

x = 8

Substitute x = 8 into 5x - 6

5x - 6 = (5 × 8) - 6 = 40 - 6 = 34

4 0
3 years ago
Find the 63rd term of the arithmetic sequence -1, 5, 11, ...−1,5,11,...
Ugo [173]

Answer:

a_6_3=371

Step-by-step explanation:

we know that

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant and this constant is called the common difference

we have

-1,5,11,...

Let

a_1=-1\\a_2=5\\a_3=11

a_2-a_1=5-(-1)=5+1=6

a_3-a_2=11-5=6

The common difference is d=6

We can write an Arithmetic Sequence as a rule

a_n=a_1+d(n-1)

where

a_n is the nth term                

d is the common difference

a_1 is the first term

n is the number of terms

Find the 63rd term of the arithmetic sequence

we have

n=63\\d=6\\a_1=-1

substitute

a_6_3=-1+6(63-1)

a_6_3=-1+6(62)

a_6_3=-1+372

a_6_3=371

6 0
3 years ago
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