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3 years ago

Find the measure of z. A. 80° B. 83 ° C. 70 ° D. 87 °

Mathematics

1 answer:

Digiron [165]3 years ago

6 0

z and 100 are on the same line so the total is 180

180-100=z

80=z

Please give Brianest

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What is the expression under the radical sign in the quadratic formula called? *

morpeh [17]

<h3>Answer: C) Discriminant</h3>

The formula for the discriminant is

d = b^2 - 4ac

If d < 0, then there are no real number solutions

If d = 0, then you have exactly one real solution

If d > 0, then you have two different real number solutions

6 0

3 years ago

Gina wants to make

gavmur [86]

Answer:

6.75 pounds

Step-by-step explanation:

This question is of direct variation. We will use x as our answer. 8 is 2/3 of 12, so 4.5 should be 2/3 of x. We can now make an equation.

$4.5=\frac{2}{3} x\\4.5*\frac{3}{2} =\frac{2}{3} x*\frac{3}{2} \\6.75=x$

In order to solve the equation, we multiply both sides by the reciprocal of 2/3, which is 3/2.

* stands for multiplication

From solving our equation, we get 6.75. We can't forget the units, so the answer is 6.75 pounds.

3 0

3 years ago

Can someone please explain to me where my teacher got the -3x - 15y = -135 from? I understand how to do this but I have no idea

Phoenix [80]

Answer:

she got those numbers from the angles angle shape

Step-by-step explanation:

im middle school and i dont know how to solve this but i see its not that completad

6 0

3 years ago

Two mathematical questions attached below.

BartSMP [9]

Answer:

See below

Step-by-step explanation:

$9.( {m}^{3} {n}^{5} )^{ \frac{1}{4} } \\ = m^{\frac{3}{4}}n^{\frac{5}{4}}\\ \\ 10. \sqrt[5]{ \sqrt[4]{x} } \\ = \sqrt[5]{ {x}^{ \frac{1}{4} } } \\ = {( {x}^{ \frac{1}{4} } )}^{ \frac{1}{5} } \\ = {x}^{ \frac{1}{4} \times \frac{1}{5} } \\ = {x}^{ \frac{1}{20} } \\ \\ \sqrt[5]{ \sqrt[3]{ {a}^{2} } } \\ = \sqrt[5]{ {a}^{ \frac{2}{3} } } \\ = {( {a}^{ \frac{2}{3} } )}^{ \frac{1}{5} } \\ = {a}^{ \frac{2}{3} \times \frac{1}{5} } \\ = {a}^{ \frac{2}{15} }$

4 0

2 years ago

Help me pleazzzzzzzzeeeeeee

uranmaximum [27]

I believe it would be the second option....

6 0

3 years ago