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Serga [27]
3 years ago
14

A spherical balloon has a radius of 8.35 m and is filled with helium. how large a cargo can it lift, assuming that the skin and

structure of the balloon have a mass of 800 kg? neglect the bouyant force on the cargo volume itself.
Physics
1 answer:
rusak2 [61]3 years ago
7 0

Assuming that the densities of the gases are:

density of air, ρ1 = 1.29 kg / m^3

density of helium, ρ2 = 0.179 kg / m^3

 

Since buoyant force and weight are two forces that are in opposite direction (buoyant force is up while weight is down), therefore equate the two:

buoyant force = weight

m g = (800 + m1) g

where m is the mass of buoyancy, g is gravity and m1 is the maximum mass of the cargo

m = 800 + m1

 

We know that mass is also expressed as:

m = ρ V

where ρ is density of gas and V is volume of the sphere

Since there are two interacting gases here, therefore m is:

m = (ρ1 – ρ2) V

 

Therefore:

(ρ1 – ρ2) V = 800 + m1

(1.29 – 0.179) (4π/3) (8.35m)^3 = 800 + m1

2709.33 = 800 + m1

m1 = 1,909.33 kg

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7 0
3 years ago
Which of the following will be the best condition for bread fermentation?
dezoksy [38]

Answer:

a. Wet, soft dough at 85 degrees Fahrenheit

Explanation:

Fermentation is an anaerobic process that transforms starches into simpler substances. The rising of dough is due to fermentation.

According to Harold McGee, 85°F (29°C) is the best temperature for fermenting bread dough. Temperatures below 85°F (29°C) take  much longer to ferment, and temperatures higher than that result into unpleasant flavors in the dough.

Wet, soft dough is usually more preferable because it produces a softer bread.

3 0
3 years ago
Sam is observing the velocity of a car at different times. After three hours, the velocity of the car is 53 km/h. After six hour
Serhud [2]
For the answer to the question above, first find out the gradient. 

<span>m = rise/run </span>
<span>=(y2-y1)/(x2-x1) </span>

<span>the x's and y's are the points given: "After three hours, the velocity of the car is 53 km/h. After six hours, the velocity of the car is 62 km/h" </span>
<span>(x1,y1) = (3,53) </span>
<span>(x2,y2) = (6,62) </span>

<span>sub values back into the equation </span>
<span>m = (62-53)/(6-3) </span>
<span>m = 9/3 </span>
<span>m = 3 </span>

<span>now we use a point-slope form to find the the standard form </span>
<span>y-y1 = m(x-x1) </span>
<span>where x1 and y1 are any set of point given </span>
<span>y-53 = 3(x-3) </span>
<span>y-53 = 3x - 9 </span>
<span>y = 3x - 9 + 53 </span>
<span>y = 3x + 44 </span>

<span>y is the velocity of the car, x is the time.
</span>I hope this helps.
4 0
3 years ago
If the magnitude of the electric field in air exceeds roughly 3 ✕ 106 n/c, the air breaks down and a spark forms. for a two-di
Vlad1618 [11]

Answer: 39.8 μC

Explanation:

The magnitude of the electric field generated by a capacitor is given by:

E = \frac{V}{d}

d is the distance between the plates.

For a capacitor, charge Q = CV where C is the capacitance and V is the voltage.

C =\frac{\epsilon_o A }{d}

where A is the area of the plate and ε₀ is the absolute permittivity.

substituting, we get

E = \frac{Q}{\epsilon_o A}

It is given that the magnitude of the electric field that can exist in the capacitor before air breaks down is, E = 3 × 10⁶ N/C.

radius of the plates of the capacitor, r = 69 cm = 0.69 m

Area of the plates, A = πr² = 1.5 m²

Thus, the maximum charge that can be placed on disks without a spark is:

Q = E×ε₀×A

⇒ Q = 3 × 10⁶ N/C × 8.85 × 10⁻¹² F/m × 1.5 m² = 39.8 × 10⁻⁶ C = 39.8 μC.

8 0
3 years ago
What force is needed to accelerate a 1,000-kilogram car from a stop to 5 m/s/s?
solong [7]
That depends on how soon you want it to reach 5 m/s/s. Without friction, ANY force will accelerate the car, like a mosquito pushing on it, but a Space Shuttle booster will accelerate it at a greater rate.
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3 years ago
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