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goblinko [34]
3 years ago
8

Use the rules for significant figures to find the answer to the following addition problem: "21.4+15+17.17+4.003"

Physics
1 answer:
harina [27]3 years ago
5 0

Answer:

57.6

Explanation:

"Significant figures" refer to figures that have an actual contribution to a <em>number's value.</em>

They refer to all digits<u> except those with</u><em><u> </u></em><em><u>"leading zero,"</u></em> which means having a zero digit before a specific number. For example, in the number 0234, the significant figures are<em> 234. </em>

The rule for adding and subtracting significant figures is to <em>round off the answer to the least number of decimal places</em>. However, when it comes to multiplying and dividing significant figures, you have<em> round off the answer to the least number of significant digits.</em>

<u>Let's solve.</u>

 21.4

+15

 17.17

<u>  4.003</u>

57.573

Let's now round off to the<em> least number of decimal places</em>, which is the <em>tenths. </em>Since 0.5 is followed by a number greater than 5, we have to round it off to 6. Therefore, the answer is: 57.6

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MrRissso [65]

Answer:

The correct option is C: 0.31 s.

Explanation:

When the mass is then suddenly released we have:

F = k\Delta y

Where:

F is the force

k: is the spring constant

Δy: is the spring displacement

Since the tension in the spring is zero, the force is the weight:

F = mg

Where:

m is the mass of the object

g is the gravity

mg = k\Delta y    (1)

The oscillation period of the spring is given by:

T = 2\pi \sqrt{\frac{m}{k}}    (2)

By solving equation (1) for "k" and entering into equation (2) we have:

T = 2\pi \sqrt{\frac{m}{\frac{mg}{\Delta y}}}

T = 2\pi \sqrt{\frac{\Delta y}{g}}

Since the spring will osclliates in a position between the initial position (when it is at rest) and the final position (when the mass is released and reaches the bottom), we have Δy = 2.5 cm = 0.025 m:

T = 2\pi \sqrt{\frac{0.025 m}{10 m/s^{2}}} = 0.31 s                   

Hence, the oscillation period is 0.31 s.

The correct option is C: 0.31s.

I hope it helps you!                                                                                                      

7 0
3 years ago
Optical tweezers use light from a laser to move single atoms and molecules around. Suppose the intensity of light from the tweez
Zanzabum

(a)  3.3\cdot 10^{-6} Pa

The radiation pressure exerted by an electromagnetic wave on a surface that totally absorbs the radiation is given by

p=\frac{I}{c}

where

I is the intensity of the wave

c is the speed of light

In this problem,

I=1000 W/m^2

and substituting c=3\cdot 10^8 m/s, we find the radiation pressure

p=\frac{1000 W/m^2}{3\cdot 10^8 m/s}=3.3\cdot 10^{-6}Pa

(b) 4.4\cdot 10^{-8} m/s^2

Since we know the cross-sectional area of the laser beam:

A=6.65\cdot 10^{-29}m^2

starting from the radiation pressure found at point (a), we can calculate the force exerted on a tritium atom:

F=pa=(3.3\cdot 10^{-6}Pa)(6.65\cdot 10^{-29} m^2)=2.2\cdot 10^{-34}N

And then, since we know the mass of the atom

m=5.01\cdot 10^{-27}kg

we can find the acceleration, by using Newton's second law:

a=\frac{F}{m}=\frac{2.2\cdot 10^{-34} N}{5.01\cdot 10^{-27} kg}=4.4\cdot 10^{-8} m/s^2

6 0
4 years ago
A large storage tank, open to the atmosphere at the top and filled with water, develops a small hole in its side at a point 15.6
VladimirAG [237]

To solve this problem it is necessary to take into account the kinematic equations of motion and the change that exists in the volume flow.

By definition the change in speed is given by

v_f^2-v_i^2 = 2ax

Where,

x= distance

v_f =final velocity

v_i =initial velocity

a = acceleration

On the other hand we know that the flow of a fluid is given by

\dot{V} = Av

Where,

A = Area

v = Velocity

PART A )

Applying this equation to the previously given values we have to

v_f^2-v_i^2 = 2ax

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v_f^2=305.76

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Therefore the velocity of the water leaving the hole is 17.48m/s

PART B )

In the case of the hole we take the area of a circle, therefore replacing in the flow equation we have to,

\dot{V} = \pi r^2 v

r = \sqrt{\frac{\dot{V}}{\pi v}}

r = \sqrt{\frac{3*10^{-3}*\frac{1}{60}}{\pi (17.48)}

r = \sqrt{9.10*10^{-7}}

r = 0.54*10^{-4}

The diameter is 2 times the radius, then is 1.91*10^{-3}m or 1.91mm

<em>Note: The rate flow was converted from minutes to seconds.</em>

8 0
3 years ago
A cylinder has a length of 3.23 cm, a diameter of 1.75 cm, and a mass of 65.3 grams. What is the density of the cylinder? Based
Firlakuza [10]
Density is a value for mass, such as kg, divided by a value for volume, such as m3. Density is a physical property of a substance that represents the mass of that substance per unit volume. We calculate density as follows:

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6 0
4 years ago
Determine the frequency of light whose wavelength is 4.257 x 10-7 cm
marin [14]

v =  f (wavelength)i don't know what symbol ya'll use for wavelength so i just put the word instead.We use the greek symbol lambda.So just plug in everything you know.
wavelength=4.257×10^-7x10^-2 and
v=speed of light = 3×10^8
So you should get f= 7.04 ×10^15Hz
7 0
3 years ago
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