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goblinko [34]
2 years ago
8

Use the rules for significant figures to find the answer to the following addition problem: "21.4+15+17.17+4.003"

Physics
1 answer:
harina [27]2 years ago
5 0

Answer:

57.6

Explanation:

"Significant figures" refer to figures that have an actual contribution to a <em>number's value.</em>

They refer to all digits<u> except those with</u><em><u> </u></em><em><u>"leading zero,"</u></em> which means having a zero digit before a specific number. For example, in the number 0234, the significant figures are<em> 234. </em>

The rule for adding and subtracting significant figures is to <em>round off the answer to the least number of decimal places</em>. However, when it comes to multiplying and dividing significant figures, you have<em> round off the answer to the least number of significant digits.</em>

<u>Let's solve.</u>

 21.4

+15

 17.17

<u>  4.003</u>

57.573

Let's now round off to the<em> least number of decimal places</em>, which is the <em>tenths. </em>Since 0.5 is followed by a number greater than 5, we have to round it off to 6. Therefore, the answer is: 57.6

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Answer:

a.) L = 2.64 kgm^2/s

b.) V = 4.4 m/s

Explanation: Jessica stretches her arms out 0.60 m from the center of her body. This will be considered as radius.

So,

Radius r = 0.6 m

Mass M = 2 kg

Velocity V = 1.1 m/s

Angular momentum L can be expressed as;

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Substitute all the parameters into the formula

L = 2 × 1.1 × 0.6 = 1.32kgm^2s^-1

the combined angular momentum of the masses will be 2 × 1.32 = 2.64 kgm^2s-1

b. If she pulls her arms into 0.15 m,

New radius = 0.15 m

Using the same formula again

L = 2( MVr)

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V = 1.32/0.3

V = 4.4 m/s

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4 0
3 years ago
Consider the nearly circular orbit of Earth around the Sun as seen by a distant observer standing in the plane of the orbit. Wha
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We have that the spring constant is mathematically given as

k=2.37*10^{11}N/m

Generally, the equation for angular velocity is mathematically given by

\omega=\sqrt{k}{m}

Where

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And

\omega =\frac{2\pi}{T}

Therefore

\frac{2\pi}{T}=\sqrt{k}{n}

Hence giving spring constant k

k=m((\frac{2 \pi}{T})^2

Generally

Mass of earth m=5.97*10^{24}

Period for on complete resolution of Earth around the Sun

T=365 days

T=365*24*3600

Therefore

k=(5.97*10^{24})((\frac{2 \pi}{365*24*3600})^2

k=2.37*10^{11}N/m

In conclusion

The effective spring constant of this simple harmonic motion is

k=2.37*10^{11}N/m

For more information on this visit

brainly.com/question/14159361

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Answer:

answer is

Explanation:

because

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What is the average speed of a kangaroo that hops 60 m in 5 s ?
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