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2 years ago

Use the rules for significant figures to find the answer to the following addition problem: "21.4+15+17.17+4.003"

Physics

1 answer:

harina [27]2 years ago

5 0

Answer:

57.6

Explanation:

"Significant figures" refer to figures that have an actual contribution to a number's value.

They refer to all digits except those with "leading zero," which means having a zero digit before a specific number. For example, in the number 0234, the significant figures are 234.

The rule for adding and subtracting significant figures is to round off the answer to the least number of decimal places. However, when it comes to multiplying and dividing significant figures, you have round off the answer to the least number of significant digits.

Let's solve.

21.4

+15

17.17

4.003

57.573

Let's now round off to the least number of decimal places, which is the tenths. Since 0.5 is followed by a number greater than 5, we have to round it off to 6. Therefore, the answer is: 57.6

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A wire 2.80 m in length carries a current of 5.20 A in a region where a uniform magnetic field has a magnitude of 0.430 T. Calcu

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Question:

A wire 2.80 m in length carries a current of 5.20 A in a region where a uniform magnetic field has a magnitude of 0.430 T. Calculate the magnitude of the magnetic force on the wire assuming the following angles between the magnetic field and the current.

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Answer:

(a)5.42 N (b)6.26 N (c)5.42 N

Explanation:

From the question

Length of wire (L) = 2.80 m

Current in wire (I) = 5.20 A

Magnetic field (B) = 0.430 T

Angle are different in each part.

The magnetic force is given by

$F=I \times B \times L \times sin(\theta)$

So from data

$F = 5.20 A \times 0.430 T \times 2.80 sin(\theta)\\\\F=6.2608 sin(\theta) N$

Now sub parts

(a)

$\theta=60^{o}\\\\Force = 6.2608 sin(60^{o}) N\\\\Force = 5.42 N$

(b)

$\theta=90^{o}\\\\Force = 6.2608 sin(90^{o}) N\\\\Force = 6.26 N$

(c)

$\theta=120^{o}\\\\Force = 6.2608 sin(120^{o}) N\\\\Force = 5.42 N$

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Answer:

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