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Colt1911 [192]
2 years ago
14

If you run around a circular track with a radius of 10m, what is the displacement after 3 full laps back to the start line?

Physics
1 answer:
Svetach [21]2 years ago
8 0

Displacement will be zero.

<h3>What is displacement and how is it different from distance?</h3>

Displacement:

  1. It is the shortest distance between an object's beginning position and ending position.
  2. The quantity is a vector.
  3. It may be zero, positive, or negative.
  4. Displacement may be greater than or equal to distance.

In the given question, we start from one point and finish at the same point around the circular track. Therefore there is no distance between the initial and final points because they are the same. That's why the displacement is zero.

Distance:

  1. It is the actual path or distance that an object takes to go from its starting point to its finishing point.
  2. The quantity is a scalar one.
  3. It cannot be 0 or negative; it must be positive.
  4. Displacement and distance may be equal.

Learn more about displacement here:

brainly.com/question/14637077

#SPJ4

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What is the final velocity of a body if it is moving with 13 m/s in 300 seconds and its acceleration is 30 m/s 2.
Nutka1998 [239]

Answer:

9013m/s

Explanation:

acceleration= v- u/ t

=> at = v-u

=> v = at + u

=> v =30*300+13

= 9013m/s

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3 years ago
A 1000.kg car moving at north at 100. km/hr brakes to a stop in 50. m within a uniform acceleration. what are magnitude and dire
Marianna [84]

Answer:

Force=7.71KN in the opposite direction

Explanation:

Given the mass of the car(M)=1000Kg

The initial speed of the car(u)=100km/hr

we know that 1km/hr=5/18 m/sec

100km/hr=100*5/18 m/sec=27.77m/sec

the distance travelled before it stops (s)=50m

let the acceleration of the car be a

The final velocity of the car is 0.

we know that  v^{2}-u^{2}=2as

0^{2}-27.77^{2}=2(-a)(50)

a=7.712m/sec^{2}

We know that F=Ma

F=1000* 7.712=7712N=7.71KN

6 0
3 years ago
8. A rectangle is measured to be 6.4 +0.2 cm by 8.3 $0.2 cm.
mamaluj [8]

Answer:

a) The perimeter of the rectangle is 29.4 centimeters.

b) The uncertainty in its perimeter is 0.8 centimeters.

Explanation:

a) From Geometry we remember that the perimeter of the rectangle (p), measured in centimeters, is represented by the following formula:

p = 2\cdot (w+l) (1)

Where:

w - Width, measured in centimeters.

l - Length, measured in centimeters.

If we know that w = 6.4\,cm and l = 8.3\,cm, then the perimeter of the rectangle is:

p = 2\cdot (6.4\,cm+8.3\,cm)

p = 29.4\,cm

The perimeter of the rectangle is 29.4 centimeters.

b) The uncertainty of the perimeter (\Delta p), measured in centimeters, is estimated by differences. That is:

\Delta p = 2\cdot (\Delta w + \Delta l)  (2)

Where:

\Delta w - Uncertainty in width, measured in centimeters.

\Delta l - Uncertainty in length, measured in centimeters.

If we know that \Delta w = 0.2\,cm and \Delta l = 0.2\,cm, then the uncertainty in perimeter is:

\Delta p = 2\cdot (0.2\,cm+0.2\,cm)

\Delta p = 0.8\,cm

The uncertainty in its perimeter is 0.8 centimeters.

5 0
3 years ago
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