The work to stretch a spring from its rest position is
(1/2) (spring constant) (distance of the stretch)²
E = 1/2 k x² .
You said it takes 1700 joules to stretch the spring 3 meters from its rest position, so we can write
1700 joules = 1/2 k (3m)²
1 joule = 1 newton-meter
1700 N-m = 1/2 k (3m)²
Multiply each side by 2: 3400 N-m = k · 9m²
Divide each side by 9m² k = 3400 N-m / 9m²
= (377 and 7/9) newton per meter
Answer:
1,780,000 N
Explanation:
0.2 atm × (1.013×10⁵ Pa/atm) = 20,260 Pa
Force = pressure × area
F = 20,260 Pa × (3.89 m × 22.6 m)
F = 1,780,000 N
