The work and heat transfer isothermal internally reversible process.
An isothermal procedure is a thermodynamic procedure in which the temperature of a gadget stays consistent. The transfer of heat into or out of the gadget occurs so slowly that thermal equilibrium is maintained. The melting of ice at 0 diploma is an example of isothermal technique. The reaction in a warmth pump is an example of isothermal manner. In Isothermal manner temperature is constant for the duration of the procedure and follows Boyles regulation.
Given,
Gas at initially P1= 2.8 bar
P2 = 14 bar
isothermal reversible process,
Compressed pressure at 60°C
(a) R = 134a
For Refrigerant 134a R134a
At P1 = 14 bar T1 = 600C
S1 = 0.9389 KJ/Kg K
V1 = 264.64 KJ/kg
At
P2 = 2.8 bar T2 = 600C
S2 = 1.1142 KJ/Kg K
V2 = 278.56 KJ/kg
T = 60 + 273 = 333K
Q= 2 Tds
2 Q=T ſ ds
= T(S2-S1)
= 333 ( 1.1142 - 0.9389 )
= 58.3749 KJ/Kg
Heat transfer Q = 58.3749 KJ/Kg
(b) air as an ideal gas.
Q= 2 Tds
2 Q=T ſ ds
= T(S2-S1)
=T-R In P2 P1
= 333 * -0.287 In 2.8 14
= 153.81 KJ/Kg
Heat transfer Q = 153.81 KJ/Kg
W = Q - ΔV
= 28.3749 - (278.56-264.64)
= 14.4549 KJ/Kg
Work W = 14.4549 KJ/Kg
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Answer:
The net force is 21 N, and the bag will go to the right.
Explanation:
You can find the net force by adding both values of the boy and the girl, and then subtracting four from it. You can also figure out which direction its moving by looking at which side is exerting the most force, which would be the right side.
<em>Hope </em><em>it </em><em>helps</em><em>!</em>
Answer:
The formula for density is d = M/V, where d is density, M is mass, and V is volume. Density is commonly expressed in units of grams per cubic centimetre.
Explanation:
have a beautiful day ahead
Answer: That depends on what other components are in the same circuit
along with the 15-ohm resistor.
If there's nothing else, and the battery is connected across the 15-ohm
resistor, then when you measure the voltage across the 15-ohm resistor,
your voltmeter is also connected straight across the battery, and you read
10 volts.
Explanation:
Answer: 26.84 m/s
Explanation:
Given
Original frequency of the horn 
Apparent frequency 
Speed of sound is 
Doppler frequency is

Where,

Insert values
![\Rightarrow 246=228\left[\dfrac{340+v_o}{340-0}\right]\\\\\Rightarrow 366.84=340+v_o\\\Rightarrow v_o=26.8\ m/s](https://tex.z-dn.net/?f=%5CRightarrow%20246%3D228%5Cleft%5B%5Cdfrac%7B340%2Bv_o%7D%7B340-0%7D%5Cright%5D%5C%5C%5C%5C%5CRightarrow%20366.84%3D340%2Bv_o%5C%5C%5CRightarrow%20v_o%3D26.8%5C%20m%2Fs)
Thus, the speed of the car is 