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4 years ago

Why should photons emitted by a hotter gas have, on average, shorter wavelengths than photons emitted by a cooler gas?

Physics

1 answer:

harkovskaia [24]4 years ago

7 0

According to wein's law,

wavelength has inverse relation with temperature

so that's why hotter gas has shorter wavelength than cooler gas.

hope this answer is correct ....

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How does an air mattress protect a stunt person landing on the ground after a stunt?

Fudgin [204]

Answer:

a) It reduces the kinetic energy loss of the stunt person.

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3 years ago

How is energy involved in physical changes and in chemical changes?

GaryK [48]

During phase changes, energy changes are usually involved. For example, when solid dry ice vaporizes (physical change), carbon dioxide molecules absorb energy. Meanwhile, when liquid water becomes ice energy is released.

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4 0

3 years ago

When a charge moves between

Olin [163]

Answer:

+ 0.07 C

Explanation:

From the question given above, the following data were obtained:

Potential difference (V) = 12 V

Energy (E) = 0.418 J

Charge (Q) =?

The energy (E) , potential difference (V) and charge (Q) are related by the following equation:

E = ½QV

With the above formula, we can obtain the charge as follow:

Potential difference (V) = 12 V

Energy (E) = 0.418 J

Charge (Q) =?

E = ½QV

0.418 = ½ × Q × 12

0.418 = Q × 6

Divide both side by 6

Q = 0.418 / 6

Q = + 0.07 C

4 0

3 years ago

Read 2 more answers

A dog walking to the right with a speed of 1.5 m s 1.5 s m 1, point, 5, start fraction, start text, m, end text, divided by, s

harina [27]

Answer: 8.62

Explanation: it’s the answer. :)

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3 years ago

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The SAF operates the M113 Ultra APC.

HACTEHA [7]

The volume of the object must be no larger than $11.15 m^3$ .

Explanation:

In order for an object to be able to float in water, its density must be equal or smaller than the water density.

The density of water is:

$\rho = 1000 kg/m^3$

This means that the density of the object must be no larger than this value.

We also know that the density of an object is given by

$\rho = \frac{m}{V}$

where

m is the mass of the object

V is its volume

For the object in this problem, the mass is

$m=1.115\cdot 10^4 kg$

Therefore, we can re-arrange the equation to find its volume:

$V=\frac{m}{\rho}=\frac{1.115\cdot 10^4}{1000}=11.15 m^3$

So, the volume of the object must be no larger than $11.15 m^3$ .

Learn more about density:

brainly.com/question/5055270

brainly.com/question/8441651

#LearnwithBrainly

8 0

4 years ago