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3 years ago

Why should photons emitted by a hotter gas have, on average, shorter wavelengths than photons emitted by a cooler gas?

Physics

1 answer:

harkovskaia [24]3 years ago

7 0

According to wein's law,

wavelength has inverse relation with temperature

so that's why hotter gas has shorter wavelength than cooler gas.

hope this answer is correct ....

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Two manned satellites approach one another at a relative velocity of v = 0.150 m/s, intending to dock. The first has a mass of m

Aleksandr [31]

Answer:

= - 0.41m/s

Explanation:

Velocity of first satellite

$V_1 = \frac{m_1 -m_2}{m_1 + m_2} u$

$V_1 = \frac{(4 \times 10^3) - (7.5 \times 10^3)}{(4 \times 10^3) + (7.5 \times 10^3)} \times 0.15\\\\= -0.30435$

Velocity of the second satellite

$V_2 = \frac{2m_1}{m_1 + m_2} u$

$V_2 = \frac{2 \times 4 \times 10^3}{4 \times 10^3 + 7.5 \times 10^3} \\\\= 0.10435$

Final velocity = V(1) - V(2)

$V = -0.30435 - 0.10435\\\\= -0.4087$

≅ -0.41m/s

8 0

3 years ago

Read 2 more answers

4) A cannon shoots a cannonball of mass 5kg vertically upward from the mouth of a cannon with muzzle velocity of 7 m/s. At a hei

Ad libitum [116K]

Answer:

h =220 m

Explanation:

Given that

u = 7 m/s

Even mass will attach but this will not produce any effect on the maximum height of the ball.Because in energy conservation the effect of mass does not present.

So the final speed of the ball will be zero at the maximum height.

v² = u² - 2 g (25 + h)

0 = 7² - 2 x 10 (25 +h)

49 = 20 ( 25 +h)

49 = 500 +20 h

Here h comes out negative that is why we are taking the 70 m/s in place of 7 m/s.

0 = 70² - 2 x 10 (25 +h) ( take g =10 m/s²)

4900 = 20 ( 25 +h)

4900 = 500 +20 h

4900- 500 = 20 h

4400 = 20 h

440 = 2 h

h =220 m

5 0

2 years ago

An capacitor consists of two large parallel plates of area A separated by a very small distance d. This capacitor is connected t

scoundrel [369]

Answer:

Will be doubled.

Explanation:

For a capacitor of parallel plates of area A, separated by a distance d, such that the charges in the plates are Q and -Q, the capacitance is written as:

$C = \frac{Q}{V} = e_0\frac{A}{d}$