Self productive and it depends on how whom is behaving.
To solve this problem it is necessary to apply the definition of severity of Newtonian laws in which it is specified that gravity is defined by
![g= \frac{GM}{R^2}](https://tex.z-dn.net/?f=g%3D%20%5Cfrac%7BGM%7D%7BR%5E2%7D)
Where
G= Gravitational Constant
M = Mass of Earth
R= Radius from center of the planet
According to the information we need to find the gravity 350km more than the radius of Earth, then
![g_{ss} = \frac{GM}{R+h^2}](https://tex.z-dn.net/?f=g_%7Bss%7D%20%3D%20%5Cfrac%7BGM%7D%7BR%2Bh%5E2%7D)
![g_{ss} = \frac{6.67*10^{-11}*5.972*10^{24}}{(6371*10^3+350*10^3)^2}](https://tex.z-dn.net/?f=g_%7Bss%7D%20%3D%20%5Cfrac%7B6.67%2A10%5E%7B-11%7D%2A5.972%2A10%5E%7B24%7D%7D%7B%286371%2A10%5E3%2B350%2A10%5E3%29%5E2%7D)
![g_{ss} = 8.82m/s^2](https://tex.z-dn.net/?f=g_%7Bss%7D%20%3D%208.82m%2Fs%5E2)
Therefore the gravitational acceleration at 350km is ![8.82m/s^2](https://tex.z-dn.net/?f=8.82m%2Fs%5E2)
Answer:The net force on the block is zero.
Explanation:
Given
Block is being pulled upward along an inclined surface at a constant speed
As speed is constant and moved in a straight line along the plane therefore its velocity is also constant .
and change in velocity is equal to acceleration therefore acceleration is zero here i.e. net force is zero acting on the body.
Answer:
a) 3.43 m/s
Explanation:
Due to the law of conservation of momentum, the total momentum of the bullet - rifle system must be conserved.
The total momentum before the bullet is shot is zero, because they are both at rest, so:
![p_i = 0](https://tex.z-dn.net/?f=p_i%20%3D%200)
Instead the total momentum of the system after the shot is:
![p_f = mv+MV](https://tex.z-dn.net/?f=p_f%20%3D%20mv%2BMV)
where:
m = 0.006 kg is the mass of the bullet
M = 1.4 kg is the mass of the rifle
v = 800 m/s is the velocity of the bullet
V is the recoil velocity of the rifle
The total momentum is conserved, therefore we can write:
![p_i = p_f](https://tex.z-dn.net/?f=p_i%20%3D%20p_f)
Which means:
![0=mv+MV](https://tex.z-dn.net/?f=0%3Dmv%2BMV)
Solving for V, we can find the recoil velocity of the rifle:
![V=-\frac{mv}{M}=-\frac{(0.006)(800)}{1.4}=-3.43 m/s](https://tex.z-dn.net/?f=V%3D-%5Cfrac%7Bmv%7D%7BM%7D%3D-%5Cfrac%7B%280.006%29%28800%29%7D%7B1.4%7D%3D-3.43%20m%2Fs)
where the negative sign indicates that the velocity is opposite to direction of the bullet: so the recoil speed is
a) 3.43 m/s