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3 years ago

7

Suppose that a particular artillery piece has a range R = 9880 yards . Find its range in miles. Use the facts that 1mile=5280ft

and 3ft=1yard.

1 answer:

Solnce55 [7]3 years ago

6 0

Answer:

R = 9880 yd * 3 ft/yd / 5280 ft/mi = 5.61 mi

If you do it in steps

R = 9880 yd * 3 ft/yd = 29640 ft

R = 29640 ft / 5280 ft/mi = 5.61 mi

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If a system reliability of 0.998 is required, what reliability of two components in series is required?

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Two components in the series have dependability of $0.996$ .

We need both two components to function in order to determine the engine's reliability. Since each component has dependability of $0.998$ , we must determine the likelihood that both components will function in order to determine the engine's reliability.

The possibility that a product, system, or service will function as intended for a predetermined amount of time, or that it will run faultlessly in a predetermined environment, is known as reliability.

By multiplying each of the $10$ reliability coefficients, we may calculate this probability:

$P = 0.998^2 = 0.996004$

P is equal to $0.9966$ after being rounded to three decimal places.

The engine has a dependability rating of $0.996$ .

Hence,

Two components connected in series have dependability of $0.996$ .

<h3>What is the compound of reliability ?</h3>

Reliability and failure probability are complimentary, or $F= 1 - R$ .

In various cases, the distinctive qualities of a series arrangement will be demonstrated. $R = R 1 R 2$ is the resultant reliability of two components.

A component's reliability is assessed in light of the application for which it will be utilised. An operational profile gives a description of the situation. Software reliability can be calculated or measured.

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