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mash [69]
3 years ago
7

Suppose that a particular artillery piece has a range R = 9880 yards . Find its range in miles. Use the facts that 1mile=5280ft

and 3ft=1yard.
Physics
1 answer:
Solnce55 [7]3 years ago
6 0

Answer:

R = 9880 yd * 3 ft/yd / 5280 ft/mi = 5.61 mi

If you do it in steps

R = 9880 yd * 3 ft/yd = 29640 ft

R = 29640 ft / 5280 ft/mi = 5.61 mi

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A note has a wavelength of 0.77955 m. If the speed of sound is 343.00 m/s, what pitch is this note?
pickupchik [31]
The equation for wave speed is:

v=\lambda * f

where "v" is wave speed, "λ" is wavelength and "f" is frequency.

Given the wave speed is 343m/s and the wavelength is 0.77955m, we can rewrite the equation as:

\frac{v}{\lambda}  = f

Substituting known values, we get:

\frac{343}{0.77955} =f

f=439.9974344

The pitch that's the closest to this value is Pitch A.
4 0
3 years ago
You are standing on a log and a friend is trying to knock
WINSTONCH [101]

Answer: catching the ball is a better choice.

Explanation:

The collision of 2 objects involves involves large impact force since the force is inversely proportional to the time in which the momentum of the object changes.

Mathematically

F=\frac{\Delta p}{\Delta t}

If we catch the ball we increase the time in which the momentum of the ball is decreased thus the impact force that acts on us is lower as larger time is allowed for the ball to decrease it's momentum.

If we allow the ball to hit us the momentum of the ball changes in a short period of time thus applying a large impact force on our body thus increasing the chances of toppling.

3 0
3 years ago
What main factor determines the stages a star will follow after the main sequence?.
Artyom0805 [142]

The main factor that determines the stages a star will follow after the main sequence is the star's mass or size.

<h3>What is main sequence?</h3>

The main sequence of a star is a stage in the life cycle of that star. During the main sequence ( also called the zero age ), the star generates energy by nuclear fusion of Hydrogen atoms at the core of the star into Helium atoms. Eventually, the star runs out of hydrogen atoms, which concludes the main sequence. What happens afterward depends on the size of the star.

<h3>Low mass stars </h3>

For low-mass stars ( stars that are less than 0.1 times the mass of the sun), they slowly collapse into white dwarfs. These stars do not get hot enough to fuse helium atoms, instead hydrogen fusion continues until the whole star is filled with helium and slowly collapses into a white dwarf while it grows dimmer and colder.

<h3>Medium-sized stars</h3>

Medium-sized stars ( stars about 0.6 - 10 times the mass of our sun) become red giants. Stars similar in size to our sun are hot enough to fuse helium atoms, so towards the end of the main sequence it starts to fuse helium atoms, forming heavier elements like carbon and oxygen. The heavier elements move to the star's core due to gravity, while lighter elements like hydrogen form a shell around the core. This causes the sun to then grow in size, forming a red giant.  

<h3>Large stars</h3>

Massive stars ( greater than 10 times the mass of the sun) and super-massive stars ( more than 40 times the mass of the sun ) end up exploding into a supernova , while the dense core collapses into a neutron star or a black hole.

To know more about main sequence, check out;  

brainly.com/question/18141359

#SPJ4

5 0
1 year ago
3.
Leto [7]
One eighth of a gram will remain
3 0
3 years ago
A 250 kg flatcar 25 m long is moving with a speed of 3.0 m/s along horizontal frictionless rails. A 61 kg worker starts walking
Anna11 [10]

Answer:

x=31.09m

Explanation:

p1=p2

The momentum of flatcar and the momentum of the worker so

The velocity of the worker is:

m_{f}*v_{f}=m_{w}*v_{w}\\\\v_{f}=\frac{m_{f}*v_{f}}{m_{w}}\\v_{f}=\frac{61kg*3.0\frac{m}{s}}{250kg}\\v_{f}=0.732\frac{m}{s}

The total motion has a total velocity and is

Vt=v_{w}+v_{f}\\Vt=0.732\frac{m}{s}+3.0\frac{m}{s}\\Vt=3.732\frac{m}{s}

The time the worker take walking is

t=\frac{x}{v_{w}}\\t=\frac{25m}{3\frac{m}{s}}=8.33s

Now the total time and the total velocity determinate the motion of tha flatcar how far has moved

x=t*Vt\\x=8.33s*3.732\frac{m}{s} \\x=31.09m

5 0
3 years ago
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