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mash [69]
3 years ago
7

Suppose that a particular artillery piece has a range R = 9880 yards . Find its range in miles. Use the facts that 1mile=5280ft

and 3ft=1yard.
Physics
1 answer:
Solnce55 [7]3 years ago
6 0

Answer:

R = 9880 yd * 3 ft/yd / 5280 ft/mi = 5.61 mi

If you do it in steps

R = 9880 yd * 3 ft/yd = 29640 ft

R = 29640 ft / 5280 ft/mi = 5.61 mi

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<span>The spring constant F = kx. But The mass acting on the spring is given by F = mg. So we have F = mg = kx. So k = mg/x where m = 0.63kg and g = 9.81N and x = 2.8 cm = 0.028m. Then we have k = (0.63 * 9.81)/0.028 = 220.725N</span>
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4 years ago
PLEASE HELP I WILL GIVE BRAINLIEST  Which substances will make a salt when combined? Vinegar and tea Soda and wine Soda and ammo
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6 0
3 years ago
Read 2 more answers
Does the frequency distribution appear to have a normal distribution using a strict interpretation of the relevant​ criteria? Te
lukranit [14]

Answer:

And as we can see on the plot we have the distribution left skewed so then this distribution is not normal because we don't have a bell shaped histofram and is not symmetric.

Explanation:

Assuming the following dataset

Temperature (F)       Frequency

50-54                          2

55-59                          0

60-64                          4

65-69                          12

70-74                           7

75-79                           5

80-84                           1

For this case we can construct the histogram with the following R code.

f<-c(2,0,4,12,7,5,1)

> barplot(f)

And the result is on the figure attached.

And as we can see on the plot we have the distribution left skewed so then this distribution is not normal because we don't have a bell shaped histofram and is not symmetric.

4 0
3 years ago
A car starts from rest and accelerates uniformly over a time of 7 seconds for a distance of 190m. Find the the acceleration of t
Mama L [17]

Answer:

a = 7.75 [m/²]

Explanation:

To solve this problem we must use the following equation of kinematics.

x=x_{0} +v_{o} *t + (\frac{1}{2})*a*t^{2}

where:

x = final distance = 190 [m]

Xo =  initial distance = 0

Vo = initial velocity = 0 (car starts from the rest)

a = acceleration [m/s²]

t = time = 7 [s]

190 = 0 + (0*7) + 0.5*a*(7²)

190 = 0.5*49*a

a = 7.75 [m/²]

4 0
3 years ago
This problem has been solved!
RideAnS [48]

Answer:

Option (a)

Explanation:

We will discard options that don't fit the situation:

Option b: <em>Incorrect </em>since if the driver "hits the gas" then velocity is augmenting and it's not constant.

Option c and d: <em>Incorrect </em>since the situation doesn't give us any information that could be related directly to the terrain or movement direction.

Option a: Correct. At <em>stage 1</em> we can assume the driver was going at constant speed which means acceleration is constantly zero. At <em>stage 2 </em>we can assume the driver augmented speed linearly, this is, with constant positive acceleration. At <em>stage 3 </em>we can assume the driver slowed the speed linearly, with constant negative acceleration.

6 0
3 years ago
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