<span>The spring constant F = kx. But The mass acting on the spring is given by F = mg.
So we have F = mg = kx.
So k = mg/x where m = 0.63kg and g = 9.81N and x = 2.8 cm = 0.028m.
Then we have k = (0.63 * 9.81)/0.028 = 220.725N</span>
Answer:
And as we can see on the plot we have the distribution left skewed so then this distribution is not normal because we don't have a bell shaped histofram and is not symmetric.
Explanation:
Assuming the following dataset
Temperature (F) Frequency
50-54 2
55-59 0
60-64 4
65-69 12
70-74 7
75-79 5
80-84 1
For this case we can construct the histogram with the following R code.
f<-c(2,0,4,12,7,5,1)
> barplot(f)
And the result is on the figure attached.
And as we can see on the plot we have the distribution left skewed so then this distribution is not normal because we don't have a bell shaped histofram and is not symmetric.
Answer:
a = 7.75 [m/²]
Explanation:
To solve this problem we must use the following equation of kinematics.

where:
x = final distance = 190 [m]
Xo = initial distance = 0
Vo = initial velocity = 0 (car starts from the rest)
a = acceleration [m/s²]
t = time = 7 [s]
190 = 0 + (0*7) + 0.5*a*(7²)
190 = 0.5*49*a
a = 7.75 [m/²]
Answer:
Option (a)
Explanation:
We will discard options that don't fit the situation:
Option b: <em>Incorrect </em>since if the driver "hits the gas" then velocity is augmenting and it's not constant.
Option c and d: <em>Incorrect </em>since the situation doesn't give us any information that could be related directly to the terrain or movement direction.
Option a: Correct. At <em>stage 1</em> we can assume the driver was going at constant speed which means acceleration is constantly zero. At <em>stage 2 </em>we can assume the driver augmented speed linearly, this is, with constant positive acceleration. At <em>stage 3 </em>we can assume the driver slowed the speed linearly, with constant negative acceleration.