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djyliett [7]
3 years ago
7

A reporter wants to investigate the reasons for the high levels of air pollution in a locality. Initial research reveals two pos

sible sources: an old thermal power plant and a sheet metal factory. She hands out the questionnaire above to the local residents to investigate the matter further. What can be concluded about the results of her investigation? A) It would help to get to the root cause of the air pollution in the locality. B) It would help her take people's opinions and shut down both the sources of pollution. C) It would be biased because no questions about the sheet metal factory have been asked. D) It would be inconclusive because there are no questions about the nature of the pollutants.
Chemistry
1 answer:
irga5000 [103]3 years ago
5 0
<h2><u><em>Answer:</em></u></h2><h2><u><em>The correct answer is C</em></u></h2><h2><u><em>Explanation:</em></u></h2><h2><u><em>An unbiased investigation would involve questions about both possible sources of pollution. However, the reporter’s questionnaire only asks questions on the power plant. The results of her investigation would be biased because no questions about the sheet metal factory have been asked.</em></u></h2><h2><u><em>Mark me the brainliest </em></u></h2><h2><u><em>PLZ</em></u></h2><h2><u><em>Hit the THX button to</em></u></h2>

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The empirical formula gives the relative ratio of atoms in each element. Therefore, it simplifies the whole numbers. For example C2H6 can be reduced to CH3 because they share the greatest common factor (2). The answer to this question would be #1. C4H10 can be reduced to C2H5 because 4 and 10 are both divisible by 2. C2H5 can not be reduced any further. All of the other options do not have a greatest common factor making them a empirical formula.
4 0
2 years ago
Butane (C4 H10(g), Hf = –125.6 kJ/mol) reacts with oxygen to produce carbon dioxide (CO2 , Hf = –393.5 kJ/mol ) and water (H2 O,
WITCHER [35]

Answer: Enthalpy of combustion (per mole) of C_4H_{10} (g) is -2657.5 kJ

Explanation:

The chemical equation for the combustion of butane follows:

2C_4H_{10}(g)+4O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(8\times \Delta H^o_f_{CO_2(g)})+(10\times \Delta H^o_f_{H_2O(g)})]-[(1\times \Delta H^o_f_{C_4H_{10}(g)})+(4\times \Delta H^o_f_{O_2(g)})]

We are given:

\Delta H^o_f_{(C_4H_{10}(g))}=-125.6kJ/mol\\\Delta H^o_f_{(H_2O(g))}=-241.82kJ/mol\\\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H^o_{rxn}=?

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.6)+(4\times 0)]\\\\\Delta H^o_{rxn}=-5315kJ

Enthalpy of combustion (per mole) of C_4H_{10} (g) is -2657.5 kJ

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Cross-linked polymers are strong and heat - resistant hence they can be used for this purpose.

A polymer is obtained by the combination of small molecules called monomers. A polymer consists of a regular repeating unit of small molecules called monomers.

A cross-linked polymer is a polymer in which covalent bonds are used to join polymer chains together. Cross-linked polymers are strong and heat - resistant hence they can be used for this purpose.

Learn more: brainly.com/question/17638582

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