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UNO [17]
3 years ago
5

Write each formula to solve for density, volume and mass.

Chemistry
1 answer:
aleksandr82 [10.1K]3 years ago
6 0
D= M/V
V= M/D
M= D x V
hope it helps!!
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Air in a closed cylinder is heated from 25 degree to 36 degree. If the initial pressure is 3.80 atm what is the final pressure ?
aleksklad [387]
Aww man, I love these types of problems!!!
So, it's a simple formula:
P1*V1/T1=P2*V2/T2

In this case, we remove V(volume) as there is none listed, leaving this:
P1/T1=P2=T2

Think you got it from here? All you gotta do is plug in the numbers and solve
If you have any further problems, just let me know!!
3 0
3 years ago
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Which object will experience the strongest gravitational attraction to Earth?
Orlov [11]

Answer:

A

Explanation:

The strength of the gravitational force between two objects depends on mass and distance. The object with the greatest mass would be the car.

3 0
3 years ago
Cuántos gramos de hidróxido de sodio (NaOH) se debe de agregar a un litro de agua para obtener una disolución al 25% en masa
Tamiku [17]

Answer:

= 250 gramos

Explanation:

No ha preguntado sobre peso / peso o peso / volumen.

Para w / v:

Simplemente tome el 25% de 1000 y luego agréguelo en 1L de agua

La masa de NaOH necesaria es de 250 g.

Para w / w:

250 gramos de NaOH y 750 g de agua, hará que la solución sea 1L.

5 0
3 years ago
A horizontal pipe 15 cm in diameter and 4 m long is buried in the earth at a depth of 20 cm. The pipe-wall temperature is 75 deg
Basile [38]

Explanation:

The given data for case (1) is as follows.

  h = 20 cm = 0.2 m

Assuming that a rectangular slab is placed above the pipe and we will calculate the heat transfer as follows.

              Q = kA \frac{\Delta T}{L}

  where,    A = area

                  L = length

                  k = thermal conductivity = 0.8 W/m

             \Delta T = change in temperature.

Therefore, putting the given values into the above formula as follows.

            Q = kA \frac{\Delta T}{L}

                = 0.8 W/m \times (4 m \times 0.15 m) \frac{75 - 5}{0.2}

                = 168 W

For case (2), h = 180 cm = 1.8 m

Therefore, heat lost will be calculated as follows.

                       Q = kA \frac{\Delta T}{L}

                           = 0.8 W/m \times (4 m \times 0.15 m) \frac{75 - 5}{1.8}

                           = 18.67 W

Thus, we can conclude that 18.67 W heat lost if the pipe was buried at a depth of 180 cm.

8 0
3 years ago
Is the following statement true or false solar panels collect energy from the sun and power a lamp and home Is the following sta
Katen [24]

The following statement is True.

8 0
3 years ago
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