Question

A TRF receiver is to be designed with a single tuned circuit using an 8.2 uH inductor. If the frequency is to be tuned from 55 kHz to 1600 kHz, find the BW that results at 550 kHz if there is exactly 10 kHz BW at a frequency of 1050 kHz.
a. 105 kHz
b. 15.24 kHz
c. 5.24 kHz
d. 10 kHz

Answer 1

Answer:

$Bw_1=5.24kHz$

Explanation:

From the question we are told that:

Induction $L=8.2uH$

Resonant Frequencies

 $F_1=550kHz\\\\\F_2=1050kHz$

Generally the Bandwidth & Frequency equation  is mathematically given by

 $\frac{F-1}{Bw_1}=\frac{F_2}{Bw_2}$

Therefore

 $Bw_1=\frac{500}{1050}*10$

 $Bw_1=5.24kHz$