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2 years ago

Is the pure fission bomb a nuclear bomb?

Engineering

1 answer:

GrogVix [38]2 years ago

8 0

Answer:

no, the pure fission bomb is a hydrogen bomb

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5 pts

Softa [21]

Answer:

Helps to accurately calculate job costs

Explanation:

please mark me as brainliest

4 0

2 years ago

Which of the following statements are true concerning AC circuit that contains both resistance and inductance? A. The current an

maw [93]

The current will lag the voltage in AC circuit that contains both resistance and inductance.

Answer: C

Explanation

There is no inductance only circuits in reality.

The circuits containing inductance has also a lower amount of resistance.

The current flows in both resistance and inductance.

There is a drop in the total voltage in resistance and inductance giving rise to the voltage applied in the coil when connected in a series.

An example being inductance coil an AC circuit connected to both resistance and inductance in series.

From the vector diagram, this conclusion can be drawn.

3 0

2 years ago

Are trains cool because if they are then my dad didn't beat me

umka2103 [35]

Answer:

I think trains are pretty awesome. There's a train in japan that levitates slightly and runs on magnetism. Pretty amazing. It's super fast too

8 0

2 years ago

During an expansion process, the pressure of a gas changes from 15 to 140 psia according to the relation P = aV + b, where a = 5

Dominik [7]

The work done during the process is 359 btu

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<u>Explanation:</u>

Given-

P1 = 15psia

P2 = 140 psia

V1 = 7ft³

a = 5 psia/ft³

b = C

P = aV +b

Work done, W = ?

P1 = aV1 + b

15 = 5 (7) + b

b = -20 psia

P2 = aV2 + b

140 = 5 ( V2) - 20

V2 = 32 ft³

The work done by the process is the area under the curve which is trapezoidal.

Therefore,

Work done, W = area of trapezoid

= (P2 + P1 / 2) (V2 - V1)

= ( 140 + 15 / 2 ) ( 32 - 7)

= 1937.5 psia ft³

= 1937.5/ 5.4039 = 359 btu

Therefore, the work done during the process is 359 btu

5 0

2 years ago

A girl operates a radio-controlled model car in a vacant parking lot. The girl's position is at the origin of the xy coordinate

lawyer [7]

Answer:

a) 17.20

b) 11.31

c) 14.42

d) 12.65

Explanation:

(a)

The girl is at the origin of the x,y coordinates (i.e 0,0,0 )

the position vector of the car at time 't' secs is

$\vec{r}= 2+2t^2, 6+t^3,0$

at t=2s, the position vector is

$\vec{r}= 10, 14,0$

Therefore, the the distance between the car and the girl is

$s= \sqrt{(10-0)^2+(14-0)^2+(0-0)^2)}\$

s = 17.20

(b)

The position of the car at t = 0s is $\vec{r}_0 = 2,6,0$

The position of the car at t = 2s is $\vec{r}_2 = 10,14,0$

The distance of the car traveled in the interval from t=0s to t=2 s is as follows:

$s_{02}= \sqrt{(10-2)^2+(14-6)^2+(0-0)^2)} \\ \\ s_{02} = 11.31$

(c)

The position vector of the car at time 't' secs is

$\vec{r}= 2+2t^2, 6+t^3,0$

The velocity of the car is

$\vec{v}=\dfrac{d\vec{r}}{dt}= 4t, 3t^2,0$

the direction of the car's velocity at t = 2s is going to be

$\vec{v}\mid _t=2 8, 12,0$

Thus; The speed of the car is

$v_{t=2}= \sqrt{8^2+12^2+0^2} \\ \\ v_{t=2}= 14.42$

(d) the car's acceleration is:

$\vec{a}=\frac{d\vec{v}}{dt}= 4, 6t,0$

The magnitude of car's acceleration at t=2s is

$\mid \vec{a}\mid _{t=2}=\sqrt{4^2+12^2+0^2} \\ \\ \mid \vec{a}\mid _{t=2}= 12.65$

5 0

2 years ago