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Soloha48 [4]
3 years ago
15

An incompressible fluid flows along a 0.20-m-diameter pipe with a uniform velocity of 3 m/s. If the pressure drop between the up

stream and downstream sections of the pipe is 20 kPa, determine the power transferred to the fluid due to fluid normal stresses.
Engineering
1 answer:
KIM [24]3 years ago
6 0

Answer:

The power transferred to the fluid is 1.8852 kW

Explanation:

Power = pressure drop × area × velocity

pressure drop = 20 kPa

area = πd^2/4 = 3.142×0.2^2/4 = 0.03142 m^2

velocity = 3 m/s

Power = 20 × 0.03142 × 3 = 1.8852 kJ/s = 1.8852 kW

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salantis [7]

Answer:

A beam is a structural member that is subjected primarily to transverse loads ... stress equal to σy, then the section Moment - Curvature (M-φ) response for .... Example 2.2 Design a simply supported beam subjected to uniformly distributed dead ... (live load). • Step I. Calculate the factored design loads (without self-weight).

Explanation:

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3 years ago
What is the correct procedure for mounting the m240 on the m122a1 tripod after the pintle is attached to the receiver?
cluponka [151]

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8 0
2 years ago
If you were to plot the voltage versus the current for a given circuit, what would you expect the slope of the line to be? If no
Brut [27]

Answer:

Part 1: It would be a straight line, current will be directly proportional to the voltage.

Part 2: The current would taper off and will have negligible increase after the voltage  reaches a certain  value. Graph attached.

Explanation:

For the first part, voltage and current have a linear relationship as dictated by the Ohm's law.

V=I*R

where V is the voltage, I is the current, and R is the resistance. As the Voltage increase, current is bound to increase too, given that the resistance remains constant.

In the second part, resistance is not constant. As an element heats up, it consumes more current because the free sea of electrons inside are moving more rapidly, disrupting the flow of charge. So, as the voltage increase, the current does increase, but so does the resistance. Leaving less room for the current to increase. This rise in temperature is shown in the graph attached, as current tapers.

7 0
4 years ago
In casting experiments performed using a certain alloy and type of sand mold, it took 155 sec for a cube-shaped casting to solid
Tems11 [23]

Answer:

A) Cm = 2.232 s/mm²

B) Time taken to solidify = 74.3 seconds

Explanation:

(A) Since a side is 50mm and all sides of a cube are equal, thus, Volume of the cube is;V = 50 x 50 x 50 = 125,000 mm³

There are 6 faces of the cube, thus Surface Area A = 6 x (50 x 50) = 15,000 mm²

So, Volume/Area = (V/A) = 125,000/15,000 = 8.333 mm

Cm is given by the formula; Cm =[Tts] /(V/A)² where Tts is time taken to solidify and it's 155 seconds in the question. Thus;

Cm = 155/(8.333)²= 2.232 s/mm²

(B) For;Cylindrical casting with D = 30 mm and L = 50 mm.;

Volume of cylinder is;

V = (πD²L) /4

So,V = (π x 30² x 50)/4 = 35,343mm³

Surface area of cylinder is;

A = (2πD²)/4 + (πDL)

Thus, A = ((π x 30²)/2) + (π x 30 x 50) = 6126 mm²

Volume/Area is;

V/A = 35,343/6126 = 5.77 mm

Same alloy and mold type was hsed as in a above, thus, Cm is still 2.232 s/mm²

Since Cm =[Tts] /(V/A)²

Making Tts the subject, we have;

Tts =Cm x (V/A)²

Tts = 2.232 x (5.77)² = 74.3 seconds

3 0
3 years ago
The change in specific internal energy depends on the path of a process. a)-True b)-False
Basile [38]

Answer:

(b) False

Explanation:

The specific internal energy of the system does not depend on the path of the process, it is a state function means its depend on only on the initial and the final position it does not depend on the path which it follow in the process.Internal energy is associated with the random motion of the molecules.

So it is false statement as internal energy is not a path function

7 0
3 years ago
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