Answer:
Explanation:
The steam turbine is modelled after the First Principle of Thermodynamics. Changes in potential and kinetic energy are negligible:
The heat rate is:
From steam and saturated tables, specific enthalpies at inlet and outlet are found:
Inlet - Superheated vapor
Outlet - Saturated vapor
The loss rate is:
Answer:
the rate of heat loss from the steam turbine is Q = 200 kW
Explanation:
From the first law of thermodynamics applied to open systems
Q-W₀ = F*(ΔH + ΔK + ΔV)
where
Q= heat loss
W₀= power generated by the turbine
F= mass flow
ΔH = enthalpy change
ΔK = kinetic energy change
ΔV = potencial energy change
If we neglect the changes in potential and kinetic energy compared with the change in enthalpy , then
Q-W₀ = F*ΔH
Q = F*ΔH+ W₀
replacing values
Q = F*ΔH+ W₀ = 420 kg/min * (-600 kJ/kg) * 1 min/60 s * 1 MW/1000 kW + 4 MW = -0.2 MW = -200 kW (negative sign comes from outflow of energy)
Answer:
Please look at attachments carefully for the ebdurance limit of each material.
Answer:
T = 15 kN
F = 23.33 kN
Explanation:
Given the data in the question,
We apply the impulse momentum principle on the total system,
mv₁ + ∑ = mv₂
we substitute
[50 + 3(30)]×10³ × 0 + FΔt = [50 + 3(30)]×10³ × ( 45 × 1000 / 3600 )
F( 75 - 0 ) = 1.75 × 10⁶
The resultant frictional tractive force F is will then be;
F = 1.75 × 10⁶ / 75
F = 23333.33 N
F = 23.33 kN
Applying the impulse momentum principle on the three cars;
mv₁ + ∑ = mv₂
[3(30)]×10³ × 0 + FΔt = [3(30)]×10³ × ( 45 × 1000 / 3600 )
F(75-0) = 1.125 × 10⁶
The force T developed is then;
T = 1.125 × 10⁶ / 75
T = 15000 N
T = 15 kN