Question

An incompressible fluid flows along a 0.20-m-diameter pipe with a uniform velocity of 3 m/s. If the pressure drop between the upstream and downstream sections of the pipe is 20 kPa, determine the power transferred to the fluid due to fluid normal stresses.

Answer 1

Answer:

The power transferred to the fluid is 1.8852 kW

Explanation:

Power = pressure drop × area × velocity

pressure drop = 20 kPa

area = πd^2/4 = 3.142×0.2^2/4 = 0.03142 m^2

velocity = 3 m/s

Power = 20 × 0.03142 × 3 = 1.8852 kJ/s = 1.8852 kW