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Masteriza [31]
3 years ago
9

For the graph of the inequality x - 2y >4, what is a value of x for a point that is on the

Mathematics
1 answer:
Colt1911 [192]3 years ago
4 0

Answer:

Step-by-step explanation:

Explanation:

First, find two points on the line if you change the inequality to an equation.

For  

x

=

0

:  

0

+

2

y

=

4

2

y

=

4

2

y

2

=

4

2

y

=

2

or  

(

0

,

2

)

For  

y

=

0

:  

x

+

0

=

4

x

=

4

or  

(

4

,

0

)

We can plot these two points and draw a line through them to get the border of the inequality:

graph{(x^2+(y-2)^2-0.075)((x-4)^2+y^2-0.075)(x+2y-4)=0}

The line will be solid because the inequality operator has a "or equal to" clause in it. We can now shade the area to the right of the line because the inequality has a "great than" clause in it.

graph{(x+2y-4)>=0}

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Pls I really need help with this question!!!!
pav-90 [236]
Answer: 43.6 (Rounded to the tenth)

Explanation: Use the method of: SOH CAH TOA.
Using TOA, T = Tangent.

tan(71) = x/15. Using the butterfly method you can just do the following equation:

15 tan(71) = 43.56 (Rounded to tenth) —> 43.6
4 0
2 years ago
A line with a slope of 0 passes through the point (-5, 6) . what is its equationin slope -intercept form?
IrinaVladis [17]

y = 6
the equation is the horizontal line which parts through (-5,6), since it has no slope.
3 0
3 years ago
Which sequence of transformations will map figure K onto figure K′? Two congruent kites, figure K and figure K prime, are drawn
elixir [45]

Answer:

The sequence of transformations will map figure K onto figure K′

is the first sequence <u>option (1)</u>

======================================================

Step-by-step explanation:

See the attached figure

as shown in the figure the K' is the image of K by reflection over x-axis

<u>But </u> We need to know which sequence of transformations will give the same result.

So, we will test the options by any point from K and its image from K'

i.e: we will test the options using the points (6,5) , (6,-5)

(6,5) ⇒ (6,-5)

<u>option (1):</u>

Reflection across x = 4, 180° rotation about the origin, and a translation of (x + 8, y)

(6,5) ⇒ (2,5) ⇒(-2,-5) ⇒ (6,-5)

<u>option (2):</u>

Reflection across x = 4, 180° rotation about the origin, and a translation of (x − 8, y)

(6,5) ⇒ (2,5) ⇒(-2,-5) ⇒ (-10,-5)

<u>option (3):</u>

Reflection across y = 4, 180° rotation about the origin, and a translation of (x + 8, y)

(6,5) ⇒ (6,3) ⇒ (-6,-3) ⇒ (2,-3)

<u>option (4):</u>

Reflection across y = 4, 180° rotation about the origin, and a translation of (x − 8, y)

(6,5) ⇒ (6,3) ⇒ (-6,-3) ⇒ (-14,-3)

As shown: The sequence of transformations will map figure K onto figure K′

is the first sequence <u>option (1)</u>

7 0
3 years ago
Read 2 more answers
Can whole numbers be rational numbers
yKpoI14uk [10]
Use this diagram, it might help.

From the inside, whatever that layer is, it can be any of the layers outside of it.

All whole numbers can be a rational number, but not all rational numbers be a whole number.

Kind of like all squares can be rectangles, but not all rectangles can be a square.

The whole number has all the attributes of a rational number, but not all rational numbers have all of the attributes of a whole number.

6 0
3 years ago
If <img src="https://tex.z-dn.net/?f=f%28x%29%3D%20%5Cfrac%7B1%7D%7Bx-2%7D%20" id="TexFormula1" title="f(x)= \frac{1}{x-2} " alt
Darina [25.2K]
I think, the answer will be -7

We have:
f(x)=1/(x-2)
g(x)
Then:
(fg)(x)=[1/(x-2)](g(x))=g(x)/(x-2)
Now; we calculate: (fg)`(x)
Remember: (u/v)=(u`v-vu´)/v²
Therefore:

(fg)´(x)=[g´(x)*(x-2) - 1*g(x)]/ (x-2)²
We know that:
g´(1)=-1
(fg)´(1)=6
Therefore:
6=[-1*(1-2)-g(1)]/(1-2)²
6=[1-g(1)]/1
6=1-g(1)
-g(1)=6-1
g(1)=-5

Answer: B. -5
4 0
4 years ago
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