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mina [271]
3 years ago
6

You have 3 five dollar bills and 4 ten dollar bills in your pocket. If you pull out 2 bills, what is the probability they are bo

th tens?
Mathematics
2 answers:
prohojiy [21]3 years ago
3 0

Answer: I think its 4%

Step-by-step explanation: 3+4=7 7/2=3.5

IceJOKER [234]3 years ago
3 0

Answer:

1/14

Step-by-step explanation:

You might be interested in
Find the values for x and y.
vivado [14]
Both sides need to equal 180 (The side with the 90 degrees measurement and the side with equations). So first subtract 180 from 90
180 - 90
to get the measurement of 5x and you get 90 but we aren't done yet since we need to find x so now we need to divide 5 by 90
90 \div 5 = 18
and we get 18 which is X.
x = 18
Now we need to find the measurement of Y. Now both angles on that side together equals 180 so we need this equation.
5(y + 11) + 4y - 10 = 180
First, distribute 5(y + 11)
5 \times y \\ 5 \times 11
Then you get this equation :
5y + 55 + 4y - 10 = 180
Now, add the two equations together
5y + 55 + 4y - 10
and you get this equation

9y + 45 = 180
Now subtract 45 from both sides
9y + 45 - 45 = 180 - 45
and divide by 9 on both sides
9y \div 9 = 135 \div 9
and you get your answer
y = 15

So
x = 18
and
y = 15
8 0
3 years ago
2. (x3 – 6x2) (x – 7)
ira [324]

Answer:

I believe this is the answer you are looking for:

x3-6x2-7x

Step-by-step explanation:

5 0
3 years ago
6)
dybincka [34]

Answer:

C

Step-by-step explanation:

both 4 and -4 are 4 units away from 0

8 0
3 years ago
Read 2 more answers
If a pool holds 22,000 gallons, how long will it take to fill the pool at a rate of 400 gallons per minute, rounded off to the n
nalin [4]
400x=22,000

22,000/400=x

55=x Hopefully this is right, and hopefully this helps
8 0
3 years ago
Read 2 more answers
The number of texts per day by students in a class is normally distributed with a 
kobusy [5.1K]

Answer:

1, 2, 6

Step-by-step explanation:

The z score shows by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean, \ \sigma=standard\ deviation

Given that mean (μ) = 130 texts, standard deviation (σ) = 20 texts

1) For x < 90:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{90-130}{20} =-2

From the normal distribution table, P(x < 90) = P(z < -2) = 0.0228 = 2.28%

Option 1 is correct

2) For x > 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

From the normal distribution table, P(x > 130) = P(z > 0) = 1 - P(z < 0) = 1 - 0.5 = 50%

Option 2 is correct

3) For x > 190:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{190-130}{20} =3

From the normal distribution table, P(x > 3) = P(z > 3) = 1 - P(z < 3) = 1 - 0.9987 = 0.0013 = 0.13%

Option 3 is incorrect

4)  For x < 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

For x > 100:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{100-130}{20} =-1.5

From the normal table, P(100 < x < 130) = P(-1.5 < z < 0) = P(z < 0) - P(z < 1.5) = 0.5 - 0.0668 = 0.9332 = 93.32%

Option 4 is incorrect

5)  For x = 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

Option 5 is incorrect

6)  For x = 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{160-130}{20} =1.5

Since 1.5 is between 1 and 2, option 6 is correct

5 0
3 years ago
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