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Assoli18 [71]
3 years ago
13

Explain why is it better to use images on hazard labels, rather than words

Chemistry
2 answers:
BigorU [14]3 years ago
8 0
Because if there actually is an emergency you might not have time to read the entire hazard label but if theres pictures it would be easier and faster than words.
enot [183]3 years ago
5 0
In the case of an emergency where you might not have enough time to read several lines of writing, not to mention trying to find the hazard warnings when the whole bottle is probably covered in writing, it is much easier to locate and read universal hazard symbols.
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Determine the identity of the daughter nuclide from the positron emission of 6832ge. determine the identity of the daughter nucl
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Answer:- The daughter nuclide is Gallium with atomic number 31 and mass number 68.

Explanations:- Positron emission is also known as beta plus decay. In this type of radioactive decay in which a proton changes into neutron and a positron and electron neutrino are released.

As the proton changes into neutron, mass number remains same but the atomic number decreases by one unit.

The given element is Ge with atomic number 32 and mass number 68. Mass number decreases by one unit means the atomic number of the daughter nuclide would be 31 and it is Gallium.

The equation could be written as:

_3_2Ge^6^8\rightarrow _3_1Ga^6^8+e^++v_e

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Right around the face/nose area

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Natasha_Volkova [10]

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https://chem.libretexts.org/Bookshelves/Physical_and_Theoretical_Chemistry_Textbook_Maps/Supplemental_Modules_(Physical_and_Theoretical_Chemistry)/Quantum_Mechanics/10%3A_Multi-electron_Atoms/Electron_Configuration

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Calculate the energy required to heat of 1.50 kg silver from -7.8 C to 15.0 C . Assume the specific heat capacity of silver unde
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Answer:

804 J

Explanation:

Step 1: Given data

  • Mass of silver (m): 1.50 kg
  • Initial temperature: -7.8 °C
  • Final temperature: 15.0 °C
  • Specific heat capacity of silver (c): 0.0235J·g⁻¹K⁻¹

Step 2: Calculate the energy required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 0.0235J·g⁻¹K⁻¹ × (1.50 × 10³g) × [15.0°C-(-7.8°C)]

Q = 804 J

5 0
3 years ago
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