Answer:
A) E = 4.96 x 10³ eV
B) E = 4.19 x 10⁴ eV
C) E = 3.73 x 10⁹ eV
Explanation:
A)
For photon energy is given as:
![E = hv](https://tex.z-dn.net/?f=E%20%3D%20hv)
![E = \frac{hc}{\lambda}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7Bhc%7D%7B%5Clambda%7D)
where,
E = energy of photon = ?
h = 6.625 x 10⁻³⁴ J.s
λ = wavelength = 0.25 nm = 0.25 x 10⁻⁹ m
Therefore,
![E = (7.95 x 10^{-16} J)(\frac{1 eV}{1.6 x 10^{-19} J})](https://tex.z-dn.net/?f=E%20%3D%20%287.95%20x%2010%5E%7B-16%7D%20J%29%28%5Cfrac%7B1%20eV%7D%7B1.6%20x%2010%5E%7B-19%7D%20J%7D%29)
<u>E = 4.96 x 10³ eV</u>
<u></u>
B)
The energy of a particle at rest is given as:
![E = m_{0}c^2](https://tex.z-dn.net/?f=E%20%3D%20m_%7B0%7Dc%5E2)
where,
E = Energy of electron = ?
m₀ = rest mass of electron = 9.1 x 10⁻³¹ kg
c = speed of light = 3 x 10⁸ m/s
Therefore,
![E = (9.1 x 10^{-31} kg)(3 x 10^8 m/s)^2\\](https://tex.z-dn.net/?f=E%20%3D%20%289.1%20x%2010%5E%7B-31%7D%20kg%29%283%20%20x%20%2010%5E8%20m%2Fs%29%5E2%5C%5C)
![E = (8.19 x 10^{-14} J)(\frac{1 eV}{1.6 x 10^{-19} J})\\](https://tex.z-dn.net/?f=E%20%3D%20%288.19%20x%2010%5E%7B-14%7D%20J%29%28%5Cfrac%7B1%20eV%7D%7B1.6%20x%2010%5E%7B-19%7D%20J%7D%29%5C%5C)
<u>E = 4.19 x 10⁴ eV</u>
<u></u>
C)
The energy of a particle at rest is given as:
![E = m_{0}c^2](https://tex.z-dn.net/?f=E%20%3D%20m_%7B0%7Dc%5E2)
where,
E = Energy of alpha particle = ?
m₀ = rest mass of alpha particle = 6.64 x 10⁻²⁷ kg
c = speed of light = 3 x 10⁸ m/s
Therefore,
![E = (6.64 x 10^{-27} kg)(3 x 10^8 m/s)^2\\](https://tex.z-dn.net/?f=E%20%3D%20%286.64%20x%2010%5E%7B-27%7D%20kg%29%283%20%20x%20%2010%5E8%20m%2Fs%29%5E2%5C%5C)
![E = (5.97 x 10^{-10} J)(\frac{1 eV}{1.6 x 10^{-19} J})\\](https://tex.z-dn.net/?f=E%20%3D%20%285.97%20x%2010%5E%7B-10%7D%20J%29%28%5Cfrac%7B1%20eV%7D%7B1.6%20x%2010%5E%7B-19%7D%20J%7D%29%5C%5C)
<u>E = 3.73 x 10⁹ eV</u>
bonsoir, je peux vous aider avec les maths laissez-moi comprendre merci