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snow_lady [41]
3 years ago
12

Iron (II) hydroxide, whose chemical formula is shown here, is soluble in different solutions. In which solution would the Iron (

III) hydroxide be LEAST soluble? A) OM (distilled water) B) 0.2M Fe3+ 0.5M Fe3- D) 1.0M Fe3-​
Physics
1 answer:
Liula [17]3 years ago
7 0

Answer:

Explanation:

b 0.2m

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What is a Newton unit? kg-m/sec2 m/sec m/sec2 m2/sec
KiRa [710]
Newton = kg . m/sec^2 
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3 years ago
You attach a 1.70 kg block to a horizontal spring that is fixed at one end. You pull the block until the spring is stretched by
Usimov [2.4K]

Answer:

maximum speed of the block is 3.14 m/s

Explanation:

given data

mass = 1.70 kg

stretch in the spring = 0.2 m

time take by block to come to zero  t = 0.2 s

solution

we know that Time period of oscillation (T) that is express as

T = 2t    ......................1

put here value

T = 2 (0.2)

T = 0.4 s

so here time period is express as

T = 2\pi \sqrt{\frac{m}{k}}     ................2

here k is spring constant of the spring so  put here value

0.4  =  2(\pi ) \sqrt{\frac{1.70}{k}}  

here k will be

k = 419.02 N/m

so we use here conservation of energy that is

Maximum kinetic energy = Maximum spring potential energy   ............3

(0.5) m v² = (0.5) k x²

here v is maximum speed block

so put here value and we get

(1.70) v² = (419.02) (0.2)²

v = 3.14 m/s

so maximum speed of the block is 3.14 m/s

8 0
2 years ago
You are making a 568b utp crossover cable that will be used to cascade two switches on an ethernet network. you have attached an
Elina [12.6K]

For a 568B crossover cable that already has wht-org and org on pins 1 and 2 of the connector at one end, the connector at the OTHER end should have wht-grn and grn on pins 1 and 2 respectively.

The wht-org and org at that end should drop to pins 3 and 6 respectively.

You're welcome, and good luck.

6 0
3 years ago
A car traveling at 37m/s starts to decelerate steadily. It comes to a complete stop in 15 seconds. What is it’s acceleration
LuckyWell [14K]

<u>Answer</u>

The acceleration is

a=-2.5ms^{-2} to the nearest tenth

<u>Explanation</u>

Since the car was travelling at 37ms^{-1} before it starts to decelerate, the initial velocity is

u=37ms^{-1}.

The final velocity is v=0ms^{-1}, because the car came to a stop.

The time taken is t=15s.

Using the Newton's equation of linear motion,

v=u +at, we find the acceleration by substituting the known values.


This implies that,

0=37 +a(15)

This gives us,

0-37=15a


\Rightarrow -37=15a


We divide both sides by 15 to get,

a=-\frac{37}{15}ms^{-2}

or

a=-2.46667ms^{-2}




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3 years ago
A period of one year on Earth is the time it takes Earth to
Kazeer [188]

D make one revolution around the sun hope this helps

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