A ladder 25 feet long is leaning against a house. The base of the ladder is pulled away at a rate of 2 ft/sec.
a.) How fast is the top of the ladder moving down the wall when the base of the ladder is 12 feet from the wall?
Answer:
dy/dt = -1.094ft/sec
Explanation:
Given that:
dz/dt = 0,
dx/dt = 2,
dy/dt = ?
Hence, we have the following
Using Pythagoras theorem
We have 25ft as the hypotenuse, y as the opposite or height of wall, and x as the base of the triangle
X² + y² = z²,
12² + y² = 25²,
y² = 25² - 12²
y = √481
Therefore, we have the following:
2x dx/dt + 2y dy/dt,
= 2z dz/dt,
= 12 (2) √481 dy/dt,
= √481 dy/dt = -24,
= dy/dt = -1.094ft/sec
Therefore, final answer is -1.094ft/sec
Explanation:
1.Pick up litter and throw it away in a garbage can.
2.Blow or sweep fertilizer back onto the grass if it gets onto paved areas. ...
3.Mulch or compost grass or yard waste. ...
4.Wash your car or outdoor equipment where it can flow to a gravel or grassed area instead of a street.
5.Don't pour your motor oil down the storm drain.
Answer:
D) The variable shown by letter C would result in a movement of the object to the right.
Explanation:
Using physical means such as electrostatic filters or mechanical filters :)
The answer to the question is sound
