Pleaseeee HURRYYY!!! How far will a train moving at 5.7 km/min go in 45 minutes
2 answers:
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Answer:
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- <u><em>1,500 kg.m/s</em></u>
Explanation:
First, arrange the information in a table:
Object Mass (kg) Velocity (m/s)
A 200 15
B 150 - 10
After the collision, the two objects are stick together, thus you talk aobut one object and one momentum.
According to the law of convervation of momentum, the momentum after the collision is equal to the momentum before the collision.
<u>Momentum before the collision, P₁</u>:
<u>Momentum after the collision</u>:
- As stated, it es equal to the momentum before the collision: 1,500 kg . m/s
Answer:
(A) 3,449,600 N/m
(B) 62,720 poeple
Explanation:
extension of the sling shot (e) = 4 m
mass of projectile (m) = 440 g = 0.44 kg
speed of projectile (v) = 11.2 km/s = 11,200 m/s
average force a person can exert = 220 N
spring constant (k) = ?
(A) When all the elastic potential energy is converted to kinetic energy
rearranging the above equation
spring constant (K) =
spring constant (K) =
spring constant (K) =
spring constant (K) = 3,449,600 N/m
(B) force required to stretch the slingshot (F) = ke = 3,449,600 x 4 = 13,798,400 N
number of people required = required force / average force per person = 13,798,400 / 220 =62,720 poeple
Answer:
A. ) K =126. 7 J
B. ) h= 91.1 m.
Explanation:
A)
- Assuming no air resistance, once released by the pitcher, the speed must keep constant through all the trajectory, so the kinetic energy of the ball can be expressed as follows:
B)
- Neglecting air resistance, total mechanical energy must be the same at any point, so, if we choose the ground level as the zero reference level for the gravitational potential energy, and assuming that the ball attains this kinetic energy just before striking ground, this value must be equal to the gravitational potential energy just before be dropped, so we can write the following equality:
⇒ m*g*h = 126. 7 J
- Solving for h, we get: