Question

Find an expression to represent the area of the triangle below.

Answer 1

Answer:

$A = \dfrac{8x}{3x + 1}$

Step-by-step explanation:

$A = \dfrac{bh}{2}$

$A = \dfrac{16x^2}{9x^2 - 1} \times \dfrac{6x^2 - 5x + 1}{2x^2 - x} \times \dfrac{1}{2}$

$A = \dfrac{(16x^2)(6x^2 - 5x + 1)}{2(9x^2 - 1)(2x^2 - x)}$

$A = \dfrac{(16x^2)(2x - 1)(3x - 1)}{2(3x - 1)(3x + 1)(x)(2x - 1)}$

$A = \dfrac{8x}{3x + 1}$