Answer:
The correct answer is option B
Explanation:
![$Molarity=\frac{Weight}{Molecular \,weight} \frac{1000}{V(in \, ml)}](https://tex.z-dn.net/?f=%24Molarity%3D%5Cfrac%7BWeight%7D%7BMolecular%20%5C%2Cweight%7D%20%5Cfrac%7B1000%7D%7BV%28in%20%5C%2C%20ml%29%7D)
Given values,
Molarity of ![$FeCl_3=0.100M$](https://tex.z-dn.net/?f=%24FeCl_3%3D0.100M%24)
Volume of solution, ![$V=250ml$](https://tex.z-dn.net/?f=%24V%3D250ml%24)
Molecular weight of ![$FeCl_3=162.2$](https://tex.z-dn.net/?f=%24FeCl_3%3D162.2%24)
Substituting this values in Molarity formula, we get
![$0.1=\frac{weight}{162.2} \times\frac{1000}{250} $\\$\Rightarrow 16.22=weight\times4$\\$\Rightarrow weight=\frac{16.22}{4} $\\$\therefore weight=4.06g$](https://tex.z-dn.net/?f=%240.1%3D%5Cfrac%7Bweight%7D%7B162.2%7D%20%5Ctimes%5Cfrac%7B1000%7D%7B250%7D%20%24%5C%5C%24%5CRightarrow%2016.22%3Dweight%5Ctimes4%24%5C%5C%24%5CRightarrow%20weight%3D%5Cfrac%7B16.22%7D%7B4%7D%20%24%5C%5C%24%5Ctherefore%20weight%3D4.06g%24)
Mixtures <span>are not chemically united, so they can be divided using physical methods.
</span>Sand is a <span>mixture. (Because different rocks have different chemical compositions.)</span>
Answer:
Commensalism is a symbiotic relationship in which one species benefits while the other species is not affected. One species typically uses the other for a purpose other than food.
Answer:The mixture is heated, boils then cooled and condenses
Explanation:
Answer:
C)52g KCl in 100g water at 80°C
Explanation:
A saturated solution is one that contains as much solute as it can dissolve in the presence of excess solute at that particular temperature.
A solutibility curve is a graph that shows the variability with temperature of the solubility of a solute in a given solvent. A solutibility curve can provide information of whether a solution formed frommthe solute and solvent are saturated or not at a given temperature.
From the solubility curve in the attachment below:
A) A saturated solution of NH₄Cl will contain about 52 g solute per 100 g sat 50 °C. Thus, a solution of 40 g NH₄Cl in 100 g water at 50 °C is an unsaturated solution.
B) A saturated solution of SO₂ at 10°C will contain about 70 g of solute in 100 g of water. Thus a solution of 2g SO₂ in 100g water at 10°C is an unsaturated solution.
C) A saturated solution of KCl at 80 °C will contain about 52 g of solute in 100 g of water. Thus, a solution of 52g KCl in 100g water at 80°C is a saturated solution.
D) A saturated solution of Kl at 20 °C will contain about 145 g of solute in 100 g of water. Thus, a solution of 120g KI in 100g water at 20°C is an unsaturated solution.