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arlik [135]
3 years ago
8

In the following structure, carbons (I),(2),(3) and (4) are classified respectively as

Chemistry
1 answer:
love history [14]3 years ago
7 0

<u>Answer:</u>

Carbon (i) : quaternary carbon

Carbon (ii) : secondary carbon

Carbon (iii) : tertiary carbon

Carbon (iv) : secondary carbon

<u>Explanation:</u>

Carbons can be classified into 4 categories:

(1) Primary carbon (1^o): These are the atoms where the carbon atom is attached to one other carbon atom.

(2) Secondary carbon (2^o): These are the atoms where the carbon atom is attached to two other carbon atoms.

(3) Tertiary carbon (3^o): These are the atoms where the carbon atom is attached to three other carbon atoms.

(4) Quaternary carbon (4^o): These are the atoms where the carbon atom is attached to four other carbon atoms.

In the given structure:

Carbon (i) is attached to 4 further carbon atoms and hence, it is a quaternary carbon.

Carbon (ii) is attached to 2 further carbon atoms and hence, it is a secondary carbon.

Carbon (iii) is attached to 3 further carbon atoms and hence, it is a tertiary carbon.

Carbon (iv) is attached to 2 further carbon atoms and hence, it is a secondary carbon.

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What is the tempature -34°C expressed in kelvins? ​
8090 [49]

Answer:

239.15 is the answer

Explanation:

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3 years ago
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Iodine monochloride (ICl) has a higher boiling point than bromine (Br2) partly because iodine monochloride is a(n)
tekilochka [14]

Answer: polar molecule.

Explanation:

The boiling point is the temperature at which the vapor pressure of a liquid equals the external pressure surrounding the liquid. The boiling point is dependent on the type of forces present.

Iodine monochloride (ICl) is a polar molecule due to the difference in electronegativities of iodine and chlorine. Thus the molecules are bonded by strong dipole dipole forces. Thus a higher temperature is needed to generate enough vapor pressure.

Bromine (Br_2) is a non polar molecule as there is no electronegativity difference between two bromine atoms. The molecules are bonded by weak vanderwaal forces and thus has low boiling point.

7 0
3 years ago
A 12.2-g sample of x reacts with a sample of y to form 78.9 g of xy. what is the mass of y that reacted?
Sonja [21]
We will assume that the only reactants are x and y and that the only product is xy.

Based on the law of mass conservation, mass is an isolated system that can neither be created nor destroyed.

Applying this concept to the chemical reaction, we will find that the total mass of the reactants must be equal to the total mass of the products,
therefore:
mass of x + mass of y = mass of xy
12.2 + mass of y = 78.9
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3 years ago
I beg you to help me in this and im gonna mark u as brainliest but fassttt
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Explanation:

F = nucleus

G = cell membrane

H = cytoplasm

J = cell wall

k = vacoule

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3 years ago
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Please I need help on these 3 questions. Thank You.​
Liula [17]

1.

V = 200 mL (volume)

c = 3 M = 3 mol/L (concentration)

First we convert mL to L:

200 mL = 0.2 L

Then we calculate the moles using the formula: n = V × c = 0.2 L × 3 mol = 0.6 mol

Finally, we just use the molar mass of CaF2 to calculate the actual mass:

molar mass = 78 g/mol

The formula is: m = n × mm (mass = moles × molar mass)

m = 0.6 mol × 78 g/mol = 46.8 g

2.

For this question the steps are exactly like the first question.

V = 50mL = 0.05 L

c = 12 M = 12 mol/L

n = V × c = 0.05 L × 12 mol/L = 0.6 mol

molar mass (HCl) = 36.5 g/mol

m = n × mm = 0.6 mol × 36.5 g/mol = 21.9 g.

3.

The steps for this question are the opposite way.

m(K2CO3) = 250 g

molar mass = 138 g/mol

n = m ÷ mm = 1.81 mol

c = 2 mol/L

V = n ÷ c = 1.81 mol ÷ 2 mol/L = 0.905 L = 905 mL

6 0
3 years ago
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