<h2>Natural Abundance for 10B is 19.60%</h2>
Explanation:
- The natural isotopic abundance of 10B is 19.60%.
- The natural isotopic abundance of 11B is 80.40%.
- The isotopic masses of boron are 10.0129 u and 11.009 u respectively.
For calculation of abundance of both the isotopes -
Supposing it was 50/50, the average mass would be 10.5, so to increase the mass we need a more percentage of 11.
Determining it as an equation -
10x + 11y= 10.8
x+y=1 (ratio)
10x + 10y = 10
By taking the denominator away from the numerator
we get;
y = 0.8
x + y = 1
∴ x = 0.2
To get percentages we need to multiply it by 100
So, the calculated abundance is 80% for 11 B and 20% 10 B.
Data:
F (force) = 22.0 N
m (mass) = ? (in Kg)
a (acceleration) = 5.5 m/s²
We apply the data to the Resultant Force formula, we have:
4.0 kg
I hope this helps. =)
A molecule may be nonpolar either when there is an equal sharing of electrons between the two atoms of a diatomic molecule or because of the symmetrical <span>arrangement of polar bonds in a more complex molecule.</span>
Explanation:
The equation is given as;
N2O(g) ⇄ N2(g) + O(g)
k₁ = Forward reaction
k₋₁ = Reverse Reaction
Equilibrium concentration (K) = k₁ / k₋₁
![K = \frac{[N2O] }{[N2] [ O]}](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B%5BN2O%5D%20%7D%7B%5BN2%5D%20%5B%20O%5D%7D)
Answer:
A. LST
Explanation:
• 1st Law: The path of each planet around the Sun is an ellipse with the Sun at one focus.
• 2nd Law: The line from the Sun to any planet sweeps out equal areas of space in equal time intervals.
• 3rd Law: The square of the orbital period of a planet is directly proportional to the cube of the average distance
